[LeetCode] Delete Duplicate Emails 刪除重復郵箱

 

Write a SQL query to delete all duplicate email entries in a table named Person, keeping only unique emails based on its smallest Id.

+----+------------------+
| Id | Email            |
+----+------------------+
| 1  | [e-mail] |
| 2  | [e-mail]  |
| 3  | [e-mail] |
+----+------------------+
Id is the primary key column for this table.

For example, after running your query, the above Person table should have the following rows:

+----+------------------+
| Id | Email            |
+----+------------------+
| 1  | [e-mail] |
| 2  | [e-mail]  |
+----+------------------+

 

這道題讓我們刪除重復郵箱，那我們可以首先找出所有不重復的郵箱，然后取個反就是重復的郵箱，都刪掉即可，那么我們如何找出所有不重復的郵箱呢，我們可以按照郵箱群組起來，然后用Min關鍵字挑出較小的，然后取補集刪除即可：

 

解法一：

DELETE FROM Person WHERE Id NOT IN
(SELECT Id FROM (SELECT MIN(Id) Id FROM Person GROUP BY Email) p);

 

我們也可以使用內交讓兩個表以郵箱關聯起來，然后把相同郵箱且Id大的刪除掉，參見代碼如下：

 

解法二：

DELETE p2 FROM Person p1 JOIN Person p2 
ON p2.Email = p1.Email WHERE p2.Id > p1.Id;

 

我們也可以不用Join，而直接用where將兩表關聯起來也行：

 

解法三：

DELETE p2 FROM Person p1, Person p2
WHERE p1.Email = p2.Email AND p2.Id > p1.Id;

 

類似題目：

Duplicate Emails

 

參考資料：

https://leetcode.com/discuss/61176/simple-solution-using-a-self-join

https://leetcode.com/discuss/48403/my-answer-delete-duplicate-emails-with-double-nested-query

 

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