sql語句獲取今天、昨天、近7天、本周、上周、本月、上月、半年數據

01    話說有一文章表article，存儲文章的添加文章的時間是add_time字段，該字段為int(5)類型的，現需要查詢今天添加的文章總數並且按照時間從大到小排序，則查詢語句如下：
02     
03    1    select * from `article` where date_format(from_UNIXTIME(`add_time`),'%Y-%m-%d') = date_format(now(),'%Y-%m-%d');
04    或者：
05     
06    1    select * from `article` where to_days(date_format(from_UNIXTIME(`add_time`),'%Y-%m-%d')) = to_days(now());
07    假設以上表的add_time字段的存儲類型是DATETIME類型或者TIMESTAMP類型，則查詢語句也可按如下寫法：
08     
09    查詢今天的信息記錄：
10     
11    1    select * from `article` where to_days(`add_time`) = to_days(now());
12    查詢昨天的信息記錄：
13     
14    1    select * from `article` where to_days(now()) – to_days(`add_time`) <= 1;
15    查詢近7天的信息記錄：
16     
17    1    select * from `article` where date_sub(curdate(), INTERVAL 7 DAY) <= date(`add_time`);
18    查詢近30天的信息記錄：
19     
20    1    select * from `article` where date_sub(curdate(), INTERVAL 30 DAY) <= date(`add_time`);
21    查詢本月的信息記錄：
22     
23    1    select * from `article` where date_format(`add_time`, ‘%Y%m') = date_format(curdate() , ‘%Y%m');
24    查詢上一月的信息記錄：
25     
26    1    select * from `article` where period_diff(date_format(now() , ‘%Y%m') , date_format(`add_time`, ‘%Y%m')) =1;
27    對上面的SQL語句中的幾個函數做一下分析：
28     
29    （1）to_days
30     
31    就像它的名字一樣，它是將具體的某一個日期或時間字符串轉換到某一天所對應的unix時間戳，如：
32     
33    01   mysql> select  to_days('2010-11-22 14:39:51');     
34    02    +--------------------------------+                                                       
35    03   | to_days('2010-11-22 14:39:51') |
36    04   +--------------------------------+
37    05   |                         734463 |
38    06   +--------------------------------+
39    07   
40    08   mysql> select  to_days('2010-11-23 14:39:51');
41    09   +--------------------------------+
42    10   | to_days('2010-11-23 14:39:51') |
43    11   +--------------------------------+
44    12   |                         734464 |
45    13   +--------------------------------+
46    可以看出22日與23日的差別就是，轉換之后的數增加了1，這個粒度的查詢是比較粗糙的，有時可能不能滿足我們的查詢要求，那么就需要使用細粒度的查詢方法str_to_date函數了，下面將分析這個函數的用法。
47     
48    提醒：
49     
50    （1）to_days() 不用於陽歷出現(1582)前的值，原因是當日歷改變時，遺失的日期不會被考慮在內。因此對於1582 年之前的日期(或許在其它地區為下一年 ), 該函數的結果實不可靠的。
51      
52    （2）MySQL"日期和時間類型"中的規則是將日期中的二位數年份值轉化為四位。因此對於'1997-10-07'和'97-10-07'將被視為同樣的日期:
53     
54    1    mysql> select to_days('1997-10-07'), to_days('97-10-07');
55    2    
56    3    -> 729669, 729669
57    （2）str_to_date
58     
59    這個函數可以把字符串時間完全的翻譯過來，如：
60     
61    1    mysql> select str_to_date("2010-11-23 14:39:51",'%Y-%m-%d %H:%i:%s');
62    2    
63    3    +--------------------------------------------------------+
64    4    | str_to_date("2010-11-23 14:39:51",'%Y-%m-%d %H:%i:%s') |
65    5    +--------------------------------------------------------+
66    6    | 2010-11-23 14:39:51                                    |
67    7    +--------------------------------------------------------+
68    具體案例操作如下：
69     
70    1    select str_to_date(article.`add_time`,'%Y-%m-%d %H:%i:%s')
71    2    from article
72    3    where str_to_date(article.`add_time`,'%Y-%m-%d %H:%i:%s')>='2012-06-28 08:00:00' and str_to_date(article.`add_time`,'%Y-%m-%d %H:%i:%s')<='2012-06-28 09:59:59';

查詢
今天
select * from 表名 where to_days(時間字段名) = to_days(now());  
昨天
 
SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) – TO_DAYS( 時間字段名) <= 1  
7天
 
SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(時間字段名)  
近30天
 
SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY) <= date(時間字段名) 

本月
 
SELECT * FROM 表名 WHERE DATE_FORMAT( 時間字段名, ‘%Y%m’ ) = DATE_FORMAT( CURDATE( ) , ‘%Y%m’ )  
上一月
 
SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , ‘%Y%m’ ) , date_format( 時間字段名, ‘%Y%m’ ) ) =1  
同時，再附上 一個 mysql官方的相關document

#查詢本季度數據
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now());
#查詢上季度數據
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));
#查詢本年數據
select * from `ht_invoice_information` where YEAR(create_date)=YEAR(NOW());
#查詢上年數據
select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year));
 
查詢當前這周的數據 
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now());
查詢上周的數據
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1;
查詢當前月份的數據
select name,submittime from enterprise   where date_format(submittime,'%Y-%m')=date_format(now(),'%Y-%m')
查詢距離當前現在6個月的數據
select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();
查詢上個月的數據
select name,submittime from enterprise   where date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m')
select * from ` user ` where DATE_FORMAT(pudate, ' %Y%m ' ) = DATE_FORMAT(CURDATE(), ' %Y%m ' ) ;
select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now())
select * 
from user 
where MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now())
select * 
from [ user ] 
where YEAR (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = YEAR (now())
and MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now())
select * 
from [ user ] 
where pudate between 上月最后一天
and 下月第一天
where   date(regdate)   =   curdate();
select   *   from   test   where   year(regdate)=year(now())   and   month(regdate)=month(now())   and   day(regdate)=day(now())
SELECT date( c_instime ) ,curdate( )
FROM `t_score`
WHERE 1
LIMIT 0 , 30