[Leetcode] Course Schedule

There are a total of n courses you have to take, labeled from 0 to n - 1.

Some courses may have prerequisites, for example to take course 0 you have to first take course 1, which is expressed as a pair: [0,1]

Given the total number of courses and a list of prerequisite pairs, is it possible for you to finish all courses?

For example:

2, [[1,0]]

There are a total of 2 courses to take. To take course 1 you should have finished course 0. So it is possible.

2, [[1,0],[0,1]]

There are a total of 2 courses to take. To take course 1 you should have finished course 0, and to take course 0 you should also have finished course 1. So it is impossible.

click to show more hints.

拓撲排序。用一個隊列存入度為0的節點，依次出隊，將與出隊節點相連的節點的入度減1，如果入度減為0，將其放入隊列中，直到隊列為空。如里最后還有入度不為0的節點的話，說明有環，否則無環。

class Solution {
public:
    bool canFinish(int numCourses, vector<vector<int>>& prerequisites) {
        vector<vector<int>> graph(numCourses, vector<int>(0));
        vector<int> inDegree(numCourses, 0);
        for (auto u : prerequisites) {
            graph[u[1]].push_back(u[0]);
            ++inDegree[u[0]];
        }
        queue<int> que;
        for (int i = 0; i < numCourses; ++i) {
            if (inDegree[i] == 0) que.push(i);
        }
        while (!que.empty()) {
            int u = que.front();
            que.pop();
            for (auto v : graph[u]) {
                --inDegree[v];
                if (inDegree[v] == 0) que.push(v);
            }
        }
        for (int i = 0; i < numCourses; ++i) {
            if (inDegree[i] != 0) return false;
        }
        return true;
    }
};