1、最簡單的內置format函數:
>>> format(1234567890,',') '1,234,567,890'
2、正則表達式:
import re def formatNum(num): num=str(num) pattern=r'(\d+)(\d{3})((,\d{3})*)' while True: num,count=re.subn(pattern,r'\1,\2\3',num) if count==0: break return num if __name__=='__main__': print formatNum(1234455)
3、最笨的倒置后遍歷過三位加逗號:
def formatNum(num): num=str(num) result='' count=0 for i in num[::-1]: count+=1 result+=i if count%3==0: result+=',' return result[::-1].strip(',') if __name__=='__main__': print formatNum(123445)