c# float和double的“坑”


定義一個float類型的變量=0.7,結果在IL中卻是0.69999999。

乘以10之后,獲取整數值。得到的卻是6。通過查看IL,竟然被轉換成double類型再轉換。就變成6了。

Demo:

QQ截圖20140626123829

IL:

.method private hidebysig static void  Main(string[] args) cil managed
{
  .entrypoint
  // 代碼大小       93 (0x5d)
  .maxstack  2
  //定義變量
  .locals init ([0] float32 val,
           [1] int32 i)
  IL_0000:  nop
  IL_0001:  ldc.r4     0.69999999
  //將0.69999999賦值給第0個變量。明明定義的是0.7
  IL_0006:  stloc.0
  IL_0007:  ldc.i4.s   10
  /將10賦值給第一個變量
  IL_0009:  stloc.1
  //double類型的0.7
  IL_000a:  ldc.r8     0.69999999999999996
  IL_0013:  ldloc.1
  IL_0014:  conv.r8
  IL_0015:  mul
  IL_0016:  call       float64 [mscorlib]System.Math::Floor(float64)
  IL_001b:  call       void [mscorlib]System.Console::WriteLine(float64)
  IL_0020:  nop
  IL_0021:  ldloc.0
  IL_0022:  call       void [mscorlib]System.Console::WriteLine(float32)
  IL_0027:  nop
  //從堆棧中加載出val
  IL_0028:  ldloc.0
  //從堆棧中加載出i
  IL_0029:  ldloc.1
  //將i轉換為float類型
  IL_002a:  conv.r4
  //val*i
  IL_002b:  mul
  //將乘法運算之后的結果轉換為double類型
  IL_002c:  conv.r8
  //調用Math.Floor對運算后的結果處理
  IL_002d:  call       float64 [mscorlib]System.Math::Floor(float64)
  IL_0032:  call       void [mscorlib]System.Console::WriteLine(float64)
  IL_0037:  nop
  IL_0038:  ldloc.0
  IL_0039:  conv.r8
  IL_003a:  call       void [mscorlib]System.Console::WriteLine(float64)
  IL_003f:  nop
  IL_0040:  ldloc.0
  IL_0041:  ldloc.1
  IL_0042:  conv.r4
  IL_0043:  mul
  IL_0044:  conv.r8
  IL_0045:  call       void [mscorlib]System.Console::WriteLine(float64)
  IL_004a:  nop
  IL_004b:  ldloc.0
  IL_004c:  conv.r8
  IL_004d:  ldloc.1
  IL_004e:  conv.r8
  IL_004f:  mul
  IL_0050:  call       void [mscorlib]System.Console::WriteLine(float64)
  IL_0055:  nop
  IL_0056:  call       string [mscorlib]System.Console::ReadLine()
  IL_005b:  pop
  IL_005c:  ret
} // end of method Program::Main


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