WPF BackgroundWorker The calling thread must be STA, because many UI components require this.【原創】

1)Issue:

      private void button1_Click(object sender, RoutedEventArgs e)
        {
            BackgroundWorker bw_test = new BackgroundWorker();
            bw_test.DoWork += new DoWorkEventHandler(bw_test_DoWork);
            bw_test.RunWorkerAsync();
        }
        
        void bw_test_DoWork(object sender, DoWorkEventArgs e)
        {
            try
            {
                //show another Forms
                InputCvtDefManul put = new InputCvtDefManul();
                put.ShowDialog();
            }
            catch (Exception ex)
            { }
        }

 Encounter this error:  The calling thread must be STA, because many UI components require this

 

2) 經過嘗試，有兩種方式可以解決:

A.這種方法網上有很多，如果不需要交互（等待顯示Form的數據），或者僅僅是更新其顯示Form的數據，這個就足夠解決了。 

       void bw_test_DoWork(object sender, DoWorkEventArgs e)
        {
            try
            {

                //InputCvtDefManul put = new InputCvtDefManul();
                //put.ShowDialog();
                Thread newWindowThread = new Thread(new ThreadStart(() =>
                        {
                            Dispatcher.Invoke(new Action(() =>
                                {
                                    InputCvtDefManul ss = new InputCvtDefManul();
                                    ss.ShowDialog();
                                }));
                        }));
                newWindowThread.Start();
                newWindowThread.SetApartmentState(ApartmentState.STA);
                newWindowThread.IsBackground = false;
                newWindowThread.Start();
            }
            catch (Exception ex)
            { }
        }

 

B.使用當前進程：

      void bw_test_DoWork(object sender, DoWorkEventArgs e)
        {
            try
            {
                System.Windows.Application.Current.Dispatcher.Invoke(DispatcherPriority.Normal, new DoMywork(ThreadStartingPoint));

                MessageBox.Show("iii", "Info", MessageBoxButton.OK, MessageBoxImage.Information);

            }
            catch (Exception ex)
            { }
        }
        private delegate void DoMywork();
        private void ThreadStartingPoint()
        {

            InputCvtDefManul put = new InputCvtDefManul();
            put.ShowDialog();
        }

 這樣的結果是只有在另起的Form關閉后才會彈出一個MessageBox。（異步）