1. 在表中插入符合主鍵 [sql] /*成績表*/ CREATE TABLE SC ( Sid INT REFERENCES Student(Sid), /*學生學號*/ Cid INT REFERENCES Course(Cid), /*課程編號*/ Score INT NOT NULL, /*課程分數*/ PRIMARY KEY(Sid,Cid) /*將學生學號和課程編號設為復合主鍵*/ ) 2. 查詢各科成績最高分,最低分以及平均分 [sql] SELECT c.Cname, MAX(s.Score) AS Max, MIN(s.Score) AS Min, AVG(s.Score) AS Average FROM Course c JOIN SC s ON c.Cid = s.Cid GROUP BY c.Cname /*此處應注意,若不按照c.Cname進行分組,SQL語句會報錯,c.Cname在SELECT語句中不合法,因為它 並未出現在聚合函數中也沒有出現在GROUP BY語句中*/ 3. 查詢平均成績大於80分的學生姓名以及平均成績 [sql] SELECT Sname, AVG(Score) AS Average FROM Student JOIN SC ON Student.Sid=SC.Sid GROUP BY Sname HAVING AVG(Score)>80 /*以聚合函數為條件進行刪選只能在HAVING語句中進行,WHERE語句不支持聚合函數*/ 4. 查詢各學生都選了多少門課 [sql] SELECT Sname, COUNT(Cid) AS TOTAL_COURSE FROM Student LEFT JOIN SC ON Student.Sid=SC.Sid GROUP BY Sname /*使用LEFT JOIN可以將一門課也沒有選的學生也查詢出來, 若不加LEFT查不出DAISY和SHERRY*/ 5. 查詢沒有選JANE老師課的學生信息 [sql] SELECT s.Sid,s.Sname,s.Sage,s.Sage FROM Student s WHERE s.Sid NOT IN (SELECT s.Sid FROM SC s JOIN Course c ON s.Cid=c.Cid JOIN Teacher t ON c.Tid=t.Tid WHERE t.Tname='JANE') /*子查詢中查詢出所有選擇JANE老師課的學生學號, 主查詢去查詢在學生表中但不在子查詢結果集中的學生信息*/ 6. 查詢既選擇了COMPUTER課程,又選擇了MATH課程的學生信息 [sql] SELECT s.Sid,s.Sname,s.Sage,s.Ssex FROM STUDENT s JOIN SC ss ON s.Sid=ss.Sid JOIN Course c ON ss.Cid=c.Cid WHERE c.Cname='COMPUTER' INTERSECT SELECT s.Sid,s.Sname,s.Sage,s.Ssex FROM STUDENT s JOIN SC ss ON s.Sid=ss.Sid JOIN Course c ON ss.Cid=c.Cid WHERE c.Cname='MATH' /*第一個查詢查詢出選擇COMPUTER課程的學生信息, 第二個查詢查詢出選擇MATH課程的學生信息, 用INTERSECT關鍵字取交集*/ 7. 查詢COMPUTER課程比MATH課程分數高的學生學號 [sql] SELECT a.Sid FROM (SELECT s.Sid,s.Score FROM SC s JOIN Course c ON s.Cid=c.Cid WHERE c.Cname='COMPUTER') a JOIN (SELECT s.Sid,s.Score FROM SC s JOIN Course c ON s.Cid=c.Cid WHERE c.Cname='MATH') b ON a.Sid=b.Sid WHERE a.Score>b.Score /*將選了COMPUTER課的學生學號和成績和選了MATH課的學生學號和成績連接 WHERE語句限制COMPUTER課的成績高於MATH課*/ 8. 查詢和JOHN選的課相同的學生信息 [sql] SELECT Student.Sname FROM Student JOIN SC ON Student.Sid=SC.Sid WHERE SC.Cid IN (SELECT SC.Cid FROM SC JOIN Student ON SC.Sid=Student.Sid WHERE Student.Sname='JOHN') /*查詢選了的課JOHN也都選了的學生的姓名*/ AND Student.Sname<>'JOHN' /*限制該學生不能是JOHN本人*/ GROUP BY Student.Sname HAVING COUNT(SC.Cid)= (SELECT COUNT(*) FROM SC JOIN Student ON SC.Sid=Student.Sid WHERE Student.Sname='JOHN') /*該學生選的課程總數與JOHN選的課程總數相同*/ 9. 按總分為學生排名,總分相同名次相同 [sql] SELECT RANK() OVER (ORDER BY SUM(ss.Score) DESC) AS Rank, s.Sname, ISNULL(SUM(ss.Score),0) FROM Student s LEFT JOIN SC ss ON s.Sid = ss.Sid GROUP BY s.Sname ORDER BY SUM(ss.Score) DESC /*RANK()是SQL Server的一個built-in函數,語法為 RANK() OVER ( [ partition_by_clause ] order_by_clause ).*/ 10. 查詢總分在100至200之間的學生姓名及總分 [sql] SELECT s.Sname,SUM(ss.Score) FROM Student s JOIN SC ss ON s.Sid=ss.Sid GROUP BY s.Sname HAVING SUM(ss.Score) BETWEEN 100 AND 200 11. 查詢總分第六到十名的學生姓名以及總分 [sql] SELECT * FROM (SELECT TOP(5) * FROM (SELECT TOP(10) SC.Sid,SUM(SC.Score) AS SUM FROM SC GROUP BY SC.Sid ORDER BY SUM(SC.Score)) a ORDER BY a.SUM) b ORDER BY b.SUM DESC /*SELECT TOP(10) SC.Sid,SUM(SC.Score) AS SUM FROM SC GROUP BY SC.Sid ORDER BY SUM(SC.Score)查詢出總分前十名 SELECT TOP(5) FROM (...) a ORDER BY a.SUM查詢出成績六到十名 SELECT * FROM (...) b ORDER BY b.SUM DESC將結果倒序按照從高分到低分排列*/ 12. 查詢各科成績的前三名以及分數 [sql] SELECT s.Sid,s.Cid,s.Score FROM SC s WHERE s.Score IN (SELECT TOP(3) Score FROM SC WHERE s.Cid= Cid ORDER BY score DESC) ORDER BY s.Cid; /*從SC表中查詢出學生學號,課程編號以及成績,WHERE子句限制了查詢出的記錄成績必須在子查詢集合內 子查詢查詢出了各科成績的前三名並通過課程編號和主查詢關聯*/ 13. 查詢有不及格科目的學生的姓名,不及格科目以及不及格科目成績 [sql] SELECT s.Sname,c.Cname,ss.Score FROM Student s JOIN SC ss ON s.Sid=ss.Sid JOIN Course c ON ss.Cid=c.Cid WHERE ss.Score<60 14. 查詢所有學生都選修的課程 [sql] SELECT c.Cname FROM SC s JOIN Course c ON s.Cid=c.Cid GROUP BY c.Cname HAVING COUNT(s.Sid)=(SELECT COUNT(*) FROM Student) 15. 查詢選修了兩門或以上的學生姓名及選修總科目 [sql] SELECT s.Sname,COUNT(ss.Cid) AS TOTAL FROM Student s JOIN SC ss ON s.Sid=ss.Sid GROUP BY s.Sname HAVING COUNT(ss.Cid)>1
