C#解析Json數組對象（利用AjaxPro實現）

1. 前端Json數組定義

  var jsonArr=new Array();
  var json1={"Name":"zhangsan","Age":15,"Sex":"male"};
  var json2={"Name":"lisi","Age":10,"Sex":"female"};
  jsonArr.push(json1);
  jsonArr.push(json2);

2. 后端：C# 定義與傳入的Json對象類似的類，用來接收Json對象
    這里要注意：傳入的Json必須和后台自定義的類的屬性值一樣。

 

    public class People
    {
        public string Name;
        public int Age;
        public string Sex;
    }

 

3. 采用AjaxPro方法傳入后端，然后利用AjaxPro.JavaScriptDeserializer類的靜態方法DeserializeFromJson(string json,Type type)
   

        [AjaxPro.AjaxMethod]
        public void DeserializeJson(object jsonObj)
        {
            List<People> lstResult = new List<People>();
            lstResult = (List<People>)JavaScriptDeserializer.DeserializeFromJson(jsonObj.ToString(), typeof(List<People>));
        }

    或者先轉換為AjaxPro.JavaScriptArray對象，然后遍歷每項，調用AjaxPro.JavaScriptDeserializer類的靜態方法Deserialize(IJavaScriptObject object,Type type)

AjaxPro.JavaScriptArray array = (AjaxPro.JavaScriptArray)JavaScriptDeserializer.DeserializeFromJson(jsonObj.ToString(), typeof(AjaxPro.JavaScriptArray));
            for (int i = 0; i < array.Count; i++)
            {
                AjaxPro.JavaScriptObject item = (AjaxPro.JavaScriptObject)array[i];
                People people=(People)AjaxPro.JavaScriptDeserializer.Deserialize(item, typeof(People));
                lstResult.Add(people);
            }