select p.*,g.roleName,pg.srcType from t_gold_pay_add p left join gRole g on p.roleID=g.roleID left join gPay pg on pg.roleID=p.roleID
這上面那邊語句,容易造成數據重復
select distinct p.id,p.*,g.roleName,pg.srcType from t_gold_pay_add p left join gRole g on p.roleID=g.roleID left join gPay pg on pg.roleID=p.roleID
加入了distinct 就好很多,但是遇到 了一個sum 求和的問題,沒有找到解決方案,手動寫的
有興趣的同學,可以告訴我一下
select distinct p.id,sum(p.gold) from t_gold_pay_add p left join gRole g on p.roleID=g.roleID left join gPay pg on pg.roleID=p.roleID