php將圖片以二進制存到mysql中的方法


很奇怪,直接用file_get_contents存入數據庫成功后,結果讀取的時候圖片不能顯示,后來解決方法是什么!!是用了下base64編碼。。。不多說直接上圖。

1.這是upload.php

<?php
include('./conn.php');
if ($_POST['submit']) {
    if ($_FILES['image']['size']) {
        $names = $_FILES['image']['name'];
        $arr   = explode('.', $names);
        $name  = $arr[0]; //圖片名稱
        $date  = date('Y-m-d H:i:s'); //上傳日期
        $fp    = fopen($_FILES['image']['tmp_name'], 'rb');
        $type  = $_FILES['image']['type'];
        $file_uploads = file_get_contents($_FILES['image']['tmp_name']);
        $file_uploads = base64_encode($file_uploads);
        if (!$fp) {
            showInfo('讀取圖片失敗!');
        } else {
            
            if ($image) {

                $q      = "insert into image (name, pic, type, date) values ('$name','$file_uploads','$type','$date')";
                $result = mysql_query($q);

                if ($result) {
                    showInfo('上傳成功!');
                } else {
                    showInfo('上傳失敗!');
                }
                mysql_close($link);
            } else {
                showInfo('請選擇要上傳的文件!');
            }
        }
        
    } else {
        showInfo('請選擇要上傳的文件!');
    }
}


function showInfo($info)
{
    echo "<html><head><meta http-equiv=\"Content-Type\" content=\"text/html; charset=utf-8\" />";
    echo "<meta http-equiv='refresh' content='1;url=show.php'>";
    echo "</head>";
    echo "<body>" . $info . "……</body>";
    echo "</html>";
}
?>


2.image.php用於從數據庫中讀取圖片

<?php
include('./conn.php');

$id     = $_GET['id'];
$sql    = "select * from image where id='$id'";
$result = mysql_query($sql);
if (!$result)
    die("讀取圖片失敗!");
$num = mysql_num_rows($result);
if ($num < 1)
    die("暫無圖片");
$obj        = mysql_fetch_object($result);
$data       = base64_decode($obj->pic);  //Base64解碼
$type = mysql_result($result, 0, 'type');
header("Content-type: $type");
echo $data;
?>

3.show.php顯示和上傳圖片

<?php
include('./conn.php');
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
       "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<html xmlns="http://www.w3.org/1999/xhtml" lang="en_US" xml:lang="en_US">

 <head>
 <meta http-equive="Content-Type" content=text/html charset=utf-8>
  <title> </title>
 </head>
 <body>
 <form method='post' action='./upload.php' enctype="multipart/form-data">
<input type="file" name="image" />
<input type="submit" name="submit" value="上傳" />
</form>
<!-----------顯示圖片--------------------->
<table>
<?php
$ret = mysql_query('select * from image order by id desc');
if ($ret) {
    while ($row = mysql_fetch_array($ret)) {
?>
<tr>
<td style='width:170px;'>
<img src="image.php?id=<?php
        echo $row[id];
?>"  width="170" height="150" border="0">
<div style='text-align:center;'><?php
        echo $row['name'];
?></div>
<?php
        echo $row['date'];
?>
</td>
</tr>
<?php
    }
}
?>
</table>
<!-----------/顯示圖片--------------------->
 </body>
</html>

 

最后運行結果:

 

 

總結:網上的都是坑爹么?誰有其他不用base64編碼的方法能否告知?


免責聲明!

本站轉載的文章為個人學習借鑒使用,本站對版權不負任何法律責任。如果侵犯了您的隱私權益,請聯系本站郵箱yoyou2525@163.com刪除。



 
粵ICP備18138465號   © 2018-2025 CODEPRJ.COM