Hibernate中Restrictions類的方法簡介（轉）

org.hibernate.criterion.Restrictions

HQL(Hibernate Query Language) 和 Criteria   都是面向對象的查詢，只不過Criteria更面向對象，Criteria和Restrictions這個類連用來實現條件查詢

下面給出一個小例子：

這里只列出其中一個頁面，其它頁面都沒有列出，主要是讓大家看看Query和Criteria怎么用

首先是Query的用法：

package cn.itcast.hibernate.domain;
import java.util.ArrayList;
import java.util.Date;
import java.util.List;
import org.hibernate.Query;
import org.hibernate.Session;
import cn.itcast.hibernate.method.MethodManager;
public class QueryTest {
/**
* @param args
*/
public static void main(String[] args) {
   User user = new User();
  
   for(int i=1; i<5; i++) {
    user.setName("Aaron"+i);
    user.setBirthday(new Date());
    MethodManager.addUser(user);//保存數據
   }
   User ss = new User();
   ss.setName("Aaron1");
   ss.setBirthday(new Date());
   MethodManager.addUser(ss);
  
   User ss1 = new User();
   ss1.setName("Aaron1");
   ss1.setBirthday(new Date());
MethodManager.addUser(ss1);
  
  query("Aaron1");
}
@SuppressWarnings("unchecked")
static void query(String userName){
   Session session = null;
   try{
    session = HibernateUtils.getSession();
    String hql = "from User user where user.name = ?";
    //String hql1 = "from User user where user.name.birthday is not null"; //多個屬性不為空
    //String hql = "from User as user where user.name = :ss";
    Query query = session.createQuery(hql);
    query.setString(0, userName);//問號的位置從0開始
   //query.setString("ss", userName);//當多個問號時，可以指定別名，這樣可以防止混亂
   
    query.setFirstResult(0);//表示從結果集的第一條記錄開始
    query.setMaxResults(10);//表示每次取20條記錄，這樣可以實現跨數據庫分頁     
   List<User> list = query.list();
   /* Iterator<User> iterator = query.iterate();
    while(iterator.hasNext()){
     System.out.println(iterator.next().getName());
    } */
   
    //User u = (User)query.uniqueResult();//確定獨一無二的結果
    //System.out.println(u);
   
/*   List names = new ArrayList();
    names.add("Aaron1");
    names.add("Aaron2");
    Query q = session.createQuery("from User user where user.name in (:naa) order by user.birthday desc");
    q.setParameterList("naa", names);
   
    List<User> cats = q.list();
    for(User userList : cats){
     System.out.println(userList.getName()+","+userList.getBirthday());
    }
    *///查詢條件是一個集合
  
    for(User userList : list){
     System.out.println(userList.getName()+","+userList.getBirthday());
    }
   } finally {
    if(session!=null)
     session.close();//必須關閉session
   }
}
}

Criteria的用法：

package cn.itcast.hibernate.domain;
import java.util.Date;
import java.util.List;
import org.hibernate.Criteria;
import org.hibernate.Session;
import org.hibernate.criterion.Restrictions;
import cn.itcast.hibernate.method.MethodManager;
public class CriteriaQuery {
/**
* @param args
*/
public static void main(String[] args) {
   User user = new User();
  
   for(int i=1; i<5; i++) {
    user.setName("Aaron"+i);
    user.setBirthday(new Date());
    MethodManager.addUser(user);//保存數據
   }
   User ss = new User();
   ss.setName("Aaron1");
   ss.setBirthday(new Date());
   MethodManager.addUser(ss);
  
   User ss1 = new User();
   ss1.setName("Aaron1");
   ss1.setBirthday(new Date());
   MethodManager.addUser(ss1);
  
   query("Aaron1");
}
@SuppressWarnings("unchecked")
static void query(String userName){
   Session session = null;
   try{
    //Criteria和Restrictions實現條件查詢
    session = HibernateUtils.getSession();
    Criteria criteria = session.createCriteria(User.class);
    criteria.add(Restrictions.eq("name", userName));
    criteria.add(Restrictions.le("birthday", new Date()));//多個add表示與
   // criteria.add(Restrictions.or(Restrictions.eq("name", userName), Restrictions.eq("name", "Aaron2")));//表示邏輯或，表示名字為Aaron和Aaron1的都查詢出來
   criteria.addOrder(Order.desc("id")); //按照id倒序
    //criteria.setFirstResult(0);
    //criteria.setMaxResults(30);
    List<User> list = criteria.list();
    for(User userList : list){
     System.out.println(userList.getName()+","+userList.getBirthday());
    }
   } finally {
    if(session!=null)
     session.close();//必須關閉session
   }
}
}

文章出處：http://hi.baidu.com/quandang/item/18cc13dc228b2c50d63aaec0