Scala List的排序函數sortWith

//原始方法：

//val list=List("abc","bcd","cde")

scala> list.sortWith( (s,t) => s.compareTo(t) <0 )

res1: List[String] = List(abc,bcd,cde)

//匿名方法:

scala> list.sortWith( _.compareTo(_) <0 )

res2: List[String] = List(abc,bcd,cde)

//上述為字典序遞增，若遞減則改'<'為'>'即可