1.一道SQL語句面試題，關於group by表內容：
info 表
date result
2005-05-09 win
2005-05-09 lose
2005-05-09 lose
2005-05-09 lose
2005-05-10 win
2005-05-10 lose
2005-05-10 lose
如果要生成下列結果, 該如何寫sql語句?
win lose
2005-05-09 2 2
2005-05-10 1 2
答案：
(1) select date, sum(case when result = "win" then 1 else 0 end) as "win", sum(case when result = "lose" then 1 else 0 end) as "lose" from info group by date;
(2) select a.date, a.result as win, b.result as lose
from
(select date, count(result) as result from info where result = "win" group by date) as a
join
(select date, count(result) as result from info where result = "lose" group by date) as b
on a.date = b.date;
2.表中有A B C三列,用SQL語句實現：當A列大於B列時選擇A列否則選擇B列，當B列大於C列時選擇B列否則選擇C列
select (case when a > b then a else b end), (case when b > c then b else c end) from table;
3.請取出tb_send表中日期(SendTime字段)為當天的所有記錄? (SendTime字段為datetime型，包含日期與時間)
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select * from tb where datediff(dd,SendTime,getdate())=0
4.有一張表，里面有3個字段：chinese，math，english。其中有一條記錄chinese 70分，math 80分，english 58分，請用一條sql語句查詢出所有記錄並按以下條件顯示出來（並寫出您的思路）：
大於或等於80表示excellent，大於或等於60表示pass，小於60分表示fail。
顯示格式： 以上面的chinese 70分，math 80分，english 58分
chinese math english
pass excellent fail
select (case when chinese >= 80 then "excellent" when chinese >= 60 then "pass" else "fail" end) as chinese,
(case when math >= 80 then "excellent" when math >= 60 then "pass" else "fail" end) as math,
(case when english >= 80 then "excellent" when english >= 60 then "pass" else "fail" end) as english
from grade;
5.請用一個sql語句得出結果
從table1,table2中取出如table3所列格式數據，注意提供的數據及結果不准確，只是作為一個格式向大家請教。
如使用存儲過程也可以。
table1
月份mon 部門dep 業績yj
-------------------------------
一月份 01 10
一月份 02 10
一月份 03 5
二月份 02 8
二月份 04 9
三月份 03 8
table2
部門dep 部門名稱dname
--------------------------------
01 國內業務一部
02 國內業務二部
03 國內業務三部
04 國際業務部
table3 （result）
部門dep 一月份 二月份 三月份
--------------------------------------
01 10 null null
02 10 8 null
03 null 5 8
04 null null 9
------------------------------------------
select t1.dep,
sum(case when mon = 1 then yj else 0 end) as jun,
sum(case when mon = 2 then yj else 0 end) as feb,
sum(case when mon = 3 then yj else 0 end) as mar
from
t1 right join t2 on t1.dep = t2.dep
group by t1.dep;