SQL 2005中合並多行記錄為一條記錄的方法總匯

--1. 創建表，添加測試數據
CREATE TABLE tb(id int, [value] varchar(10))
INSERT tb SELECT 1, 'aa'
union     ALL SELECT 1, 'bb'
union     ALL SELECT 2, 'aaa'
union     ALL SELECT 2, 'bbb'
union     ALL SELECT 2, 'ccc'

--SELECT * FROM tb
/**//*
id value
----------- ----------
1 aa
1 bb
2 aaa
2 bbb
2 ccc

(5 row(s) affected)
*/

--2 在SQL2005中的解法
----2.1 使用OUTER APPLY
SELECT * 
FROM (SELECT DISTINCT id FROM tb) A OUTER APPLY(
SELECT [values]= STUFF(REPLACE(REPLACE(
(
SELECT value FROM tb N
WHERE id = A.id
FOR XML AUTO
), '<N value="', ','), '"/>', ''), 1, 1, '')
)N

----2.2 使用XML
SELECT id, [values]=STUFF((SELECT ','+[value] FROM tb t WHERE id=tb.id FOR XML PATH('')), 1, 1, '')
FROM tb
GROUP BY id
--3 在SQL2000只能用自定義函數實現
----3.1 創建合並函數fn_strSum，根據id合並value值
GO
CREATE FUNCTION dbo.fn_strSum(@id int)
RETURNS varchar(8000)
AS
BEGIN
DECLARE @values varchar(8000)
SET @values = ''
SELECT @values = @values + ',' + value FROM tb WHERE id=@id
RETURN STUFF(@values, 1, 1, '')
END
GO

-- 調用函數
SELECT id, VALUE = dbo.fn_strSum(id) FROM tb GROUP BY id
DROP FUNCTION dbo.fn_strSum

----3.2 創建合並函數fn_strSum2，根據id合並value值
GO
CREATE FUNCTION dbo.fn_strSum2(@id int)
RETURNS varchar(8000)
AS
BEGIN
DECLARE @values varchar(8000) 
SELECT @values = isnull(@values + ',', '') + value FROM tb WHERE id=@id
RETURN @values
END
GO

-- 調用函數
SELECT id, VALUE = dbo.fn_strSum2(id) FROM tb GROUP BY id
DROP FUNCTION dbo.fn_strSum2