今天看了篇帖子,被幾個地方轉載,但是性能不太好,因為不能評論,所以把優化思路寫在這里。
1.確定需求: 根據部門來分組,顯示各員工在部門里按薪水排名名次.
2.來創建實例數據:
drop table if exists heyf_t10;
create table heyf_t10 (empid int ,deptid int ,salary decimal(10,2) );insert into heyf_t10 values(1,10,5500.00),(2,10,4500.00),(3,20,1900.00),(4,20,4800.00),(5,40,6500.00),(6,40,14500.00),(7,40,44500.00),(8,50,6500.00),(9,50,7500.00);
3. http://www.kaishixue.com/mysql/14.html 帖子中SQL的實現
select empid,deptid,salary,rank
from(select heyf_tmp.empid, heyf_tmp.deptid, heyf_tmp.salary, @rownum:=@rownum+1,if(@pdept=heyf_tmp.deptid,@rank:=@rank+1,@rank:=1) as rank,@pdept:=heyf_tmp.deptidfrom(select empid,deptid,salary from heyf_t10 order by deptid asc ,salary desc ) heyf_tmp,(select @rownum:=0, @pdept:=null,@rank:=0) a ) result;
執行計划如下
idselect_typetabletypepossible_keyskeykey_lenrefrowsfilteredExtra
1PRIMARY<derived2>ALLNULLNULLNULLNULL9100.00
2DERIVED<derived4>systemNULLNULLNULLNULL1100.00
2DERIVED<derived3>ALLNULLNULLNULLNULL9100.00
4DERIVEDNULLNULLNULLNULLNULLNULLNULLNULLNo tables used
3DERIVEDheyf_t10ALLNULLNULLNULLNULL9100.00Using filesort
如果大數據量直接就掛了。換個思路來寫
select h.`empid`,h.`deptid`,h.`salary`,count(*) as rank
from heyf_t10 as h
left outer join heyf_t10 as r
on h.deptid = r.deptid
and h.`salary`<= r.`salary`
group by h.`empid`,h.`deptid`,h.`salary`
order by h.deptid, h.salary desc;
idselect_typetabletypepossible_keyskeykey_lenrefrowsfilteredExtra
1SIMPLEhALLNULLNULLNULLNULL9100.00Using temporary; Using filesort
1SIMPLErALLNULLNULLNULLNULL9100.00
需要優化的時候建立個索引優化掉filesort,很直觀,效率也提高了很多。有時候不能太趕需求,遇到復雜的SQL還是讓DBA來優化一下。
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