獲取單個文件行數
文件:test1.sh
行數:20
方法一
awk '{print NR}' test1.sh|tail -n1
如圖所示:
方法二
awk 'END{print NR}' test1.sh
如圖所示:
方法三
grep -n "" test1.sh|awk -F: '{print '}|tail -n1
如圖所示:
方法四
sed -n '$=' test1.sh
如圖所示:
方法五
wc -l test1.sh
如圖所示:
方法六
#cat test1.sh |wc -l
如圖所示:
獲取特定目錄所有文件的行數
代碼如下:
#!/bin/bash filesCount=0 linesCount=0 function funCount() { for file in ` ls $1 ` do if [ -d $1"/"$file ];then funCount $1"/"$file else declare -i fileLines fileLines=`sed -n '$=' $1"/"$file` let linesCount=$linesCount+$fileLines let filesCount=$filesCount+1 fi done } if [ $# -gt 0 ];then for m_dir in $@ do funCount $m_dir done else funCount "." fi echo "filesCount = $filesCount" echo "linesCount = $linesCount"
使用方法:
1、針對本目錄
./count.sh
2、統計多個目錄
./count.sh /tmp ~
運行效果如下:
獲取特定目錄特定擴展名文件的行數
代碼如下:
#!/bin/bash extens=(".c" ".cpp" ".h" ".hpp") filesCount=0 linesCount=0 function funCount() { for file in ` ls $1 ` do if [ -d $1"/"$file ];then funCount $1"/"$file else fileName=$1"/"$file EXTENSION="."${fileName##*.} echo "fileName = $fileName Extension = $EXTENSION" if [[ "${extens[@]/$EXTENSION/}" != "${extens[@]}" ]];then declare -i fileLines fileLines=`sed -n '$=' $fileName` echo $fileName" : "$fileLines let linesCount=$linesCount+$fileLines let filesCount=$filesCount+1 fi fi done } if [ $# -gt 0 ];then for m_dir in $@ do funCount $m_dir done else funCount "." fi echo "filesCount = $filesCount" echo "linesCount = $linesCount"
使用方法:
1、針對本目錄
./count.sh
2、統計多個目錄
./count.sh /tmp ~
運行效果如下:
好,就這些了,希望對你有幫助。