city=["北京","上海","天津","重慶"]
puts city
city=Array.new
city[0]="北京"
city[1]="上海"
city[2]="天津"
city[3]="重慶"
puts city
city=["北京","上海","天津","重慶"]
city[4]="香港"
puts "數組的長度為："+city.size.to_s
puts city
puts "第二個元素為："+city[1]
puts "最后一個元素為："+city[-1]
city=Array.new
city[2]="香港"
puts "數組的長度為："+city.size.to_s
puts city
str="深圳"
city_1=%W{北京 上海 天津 重慶 杭州 南京 #{str}}#使用%W{...}進行轉換
puts city_1.size
puts city_1
city_2=%w{北京 上海 天津 重慶 杭州 南京 #{str}}#使用%w{...}進行轉換
puts city_2
college=["北京大學","清華大學"]
college.unshift("浙江大學","復旦大學") #向數組頭部添加元素列表
college.push("南京大學","武漢大學") #向數組尾部添加元素列表
college<<"南開大學" #向數組尾部添加一個元素
puts college.size.to_s
puts college
puts college.pop #刪除並獲取數組最后一個元素
puts college.shift #刪除並獲取數組第一個元素
puts college.size.to_s
puts college
puts college[2,3] #截取從索引2開始，長度為3的元素列表
puts college[2..3] #截取從索引2開始，到索引3的元素列表
puts college[2...3] #截取從索引2開始，到索引3(不包括)的元素列表
city_1=["北京","上海","天津"]
city_2=["重慶","香港"]
city_3=city_1+city_2
puts city_3.size.to_s
city_1.concat(city_2)
puts city_1.size.to_s
a=Array.new
p a
a=Array.new(5)
p a
a=Array.new(5,0)
p a
#lang=%W(a b c)
lang=%W{a b c}
p lang
h={"a"=>"b","c"=>"d"}
p h.to_a
s="ab cd efg"
a=s.split(" ")
p a
#p a.include?("ab")
#a.each_with_index do |b,i|
# p b
# p i
#end
#h = {:aaa => "bbb", :ccc => "ddd"}
#h.each_key do |key|
# p h[key]
#end
#h.replace({:a => "b", :c => "d"})
#p h
#t = Time.now
#p t.strftime("%y")
a=[1,2,3,5,7,9]
b=[2,4,6,8,10]
#兩數組相連
p (a+b)
#a數組中的元素減去b數組中與之相同的元素
p (a-b)
#（並集）除去兩個數組中相同的元素
p (a|b)
#（交集）只有兩個數組中都相同的元素
p (p&b)
a=[1,2,3,2]
a.delete(2) #刪除所有與X相同的元素
p a
a=[1,2,3,2]
a.delete_at(3) #刪除第n個元素
p a
a=[1,2,3,4,5,6,7,8,9,10]
a.slice!(1,5) #刪除數組中第幾到第幾個之間的所有數據
p a
a=[1,2,3,4,5,6,7]
a[1..6]=[4,5,6,7,8,9] #a[n..m]方法可以選擇改變數組
p a
a=[1,2,3,4,5,6,7,8,9]
a.each(){|s| p s}
a.each_with_index do |c,i|
puts "#{i} : #{c}"
puts (c+i).to_s
end
a=[[1,2],[2,3],[3,4],6]
p a.flatten
s = [ 1, 2, 3 ] #=> [1, 2, 3]
t = [ 4, 5, 6, [7, 8] ] #=> [4, 5, 6, [7, 8]]
a = [ s, t, 9, 10 ] #=> [[1, 2, 3], [4, 5, 6, [7, 8]], 9, 10]
puts a.flatten #=> [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
a = [ 1, 2, [3, [4, 5] ] ]
puts a.flatten(1) #=> [1, 2, 3, [4, 5]]
puts a.flatten #=> [1, 2, 3, 4, 5]
a=[1,1,2,2,3,3]
p a.uniq #去掉重復的元素
arr=[9,8,7,1,2,5,3]
p arr.sort #=> [1, 2, 3, 5, 7, 8, 9]
p arr #=> [9, 8, 7, 1, 2, 5, 3]
p arr.sort! #=> [1, 2, 3, 5, 7, 8, 9]
p arr #=> [1, 2, 3, 5, 7, 8, 9]
p arr.sort{|a,b| b<=>a}
[]
[nil, nil, nil, nil, nil]
[0, 0, 0, 0, 0]
["a", "b", "c"]
[["c", "d"], ["a", "b"]]
["ab", "cd", "efg"]
[1, 2, 3, 5, 7, 9, 2, 4, 6, 8, 10]
[1, 3, 5, 7, 9]
[1, 2, 3, 5, 7, 9, 4, 6, 8, 10]
false
[1, 3]
[1, 2, 3]
[1, 7, 8, 9, 10]
[1, 4, 5, 6, 7, 8, 9]
1
2
3
4
5
6
7
8
9
0 : 1
1
1 : 2
3
2 : 3
5
3 : 4
7
4 : 5
9
5 : 6
11
6 : 7
13
7 : 8
15
8 : 9
17
[1, 2, 2, 3, 3, 4, 6]
1
2
3
4
5
6
7
8
9
10
1
2
3
4
5
1
2
3
4
5
[1, 2, 3]
[1, 2, 3, 5, 7, 8, 9]
[9, 8, 7, 1, 2, 5, 3]
[1, 2, 3, 5, 7, 8, 9]
[1, 2, 3, 5, 7, 8, 9]
[9, 8, 7, 5, 3, 2, 1]