Ruby 數組操作方法(轉)


 

函數名稱

說明

示例

&     

                        

數組與,返回兩數組的交集      

[1,2] & [2,3] =>[2]                                               

*

 

復制數組n次

[1,2]*2       => [1,2,1,2]

+

 

返回兩數組的並集,但不排除重復元素

[1,2]+[2,3]    =>[1,2,2,3]

<< 

 

追加元素,但不排除重復元素

[1,2]<<[2,3]   => [1,2,2,3]

|

 

追加元素,但排除重復元素

[1,2] | [2,3]    => [1,2,3]

-

 

返回第一個數組與第二個數組不同的元素

[1,2]-[2,3]    => [1]

<=>

 

比較數組

[1,2]<=>[2,3] =>flase

==

 

比較數組,若所有元素均相等時返回真

[1,2]==[2,1]    =>flase

assoc

 

從數組的每個元素中尋找指定對象

[[1,2],[3,4]].assoc(2)=> [1,2]

at

找到數組的第N個元素

 

負數表示逆向查找

 

["a","b","c","d","e"].at(0) => "a"

 

["a","b","c","d","e"].at(-1)  => "e"

clear

 

刪除數組中的所有元素

 

["a","b","c","d","e"]. clear

collect

 

collect

 

用一個過程塊對數組的每個元素進行處理

["a","b","c","d"].collect {|x| x + "!" } 

 

=> ["a!", "b!", "c!", "d!"] 

compact

 

compact!

 

刪除值為nil的元素后生成新數組並返回它

["a",nil,"b",nil,"c",nil].compact 

 

=> ["a", "b", "c"] 

delete

 

刪除元素,如果元素重復,全部刪除

a = [ "a", "b", "b", "b", "c" ] 

 

a.delete("b")

 

puts a    => ["a","c"]

delete_at

刪除pos所指位置的元素並返回它。若pos超出數

組范圍則返回nil

a = %w( ant bat cat dog ) 

 

a.delete_at(2)   » "cat" 

 

a=> ["ant", "bat", "dog"] 

 

a.delete_at(99) => nil

 

delete_if

 

根據條件刪除

a = [ "a", "b", "c" ] 

 

a.delete_if {|x| x >= "b" } => ["a"] 

each

對數組的每個元素按值進行迭代操作

查尋方法find,也有:list = ['a','b','c']  list.find{|x| x=='c'}

a = [ "a", "b", "c" ]

 

a.each {|x| print x, " -- " }

 

 =>  "a -- b -- c --"

each_index

對數組的每個元素按索引進行迭代操作

a = [ "a", "b", "c" ]

 

a.each_index {|x| print x, " -- " }

 

=> "0 -- 1 -- 2 --"

empty?

判斷數組是否為空,為空則返回真

[].empty?=> true 

eql

比較兩數組是否相等

["a","b","c"].eql?(["a","b","c"]) => true 

fill

填充數組

["a","b","c","d"].fill("x") 

 

=> ["x","x","x","x"] 

 

["a","b","c","d"].fill("z", 2, 2) 

 

=> ["x", "x", "z", "z"]

first

返回數組的首元素。若沒有首元素則返回nil

[ "q", "r", "s", "t" ].first   => "q"

last

返回數組末尾的元素。若數組為空時,返回nil

["w","x","y","z"].last     => "z" 

include?

判斷數組中是否包含元素

a = [ "a", "b", "c" ] 

 

a.include?("b") => true 

 

a.include?("z") => false

index

返回數組中第一個==val的元素的位置

a = [ "a", "b", "c" ] 

 

a.index("b") => 1 

 

a.index("z") => nil 

indexes

以數組形式返回其索引值與各參數值相等的元素

a = [ "a", "b", "c", "d", "e", "f", "g" ] 

 

a.indexes(0, 2, 4)   => ["a", "c", "e"] 

 

a.indexes( 2, 4, 12)=> [ "c", "e", nil] 

insert

在索引為nth的元素前面插入第2參數以后的值

ary = %w(foo bar baz)

 

ary.insert 2,'a','b'

 

p ary => ["foo", "bar", "a", "b", "baz"]

join

將數組元素按一定的分隔符連接起來

[ "a", "b", "c" ].join=> "abc" 

 

[ "a", "b", "c" ].join("-") => "a-b-c" 

length

 

 

size

返回數組長度。若數組為空則返回0

[1,2,3].length   => 3

 

[1,2,3].size      => 3

nitems

返回非nil元素的個數

[ 1, nil, 3, nil, 5 ].nitems => 3 

pop

刪除末尾元素並返回它。若數組為空則返回nil

a = [ "a", "m", "z" ] 

 

a.pop             => "z" 

 

p a                 => ["a", "m"] 

push

添加新元素

["a","b"].push(['1','2'])

 

=>["a", "b", ["1", "2"]]

rassoc

遍歷數組每個元素(元素必須是數組),匹配索引為1的值是否與查找的字符相等,返回第一個相等的元素

a = [[15,1], [25,2], [35,2]]

 

p a.rassoc(2)         => [25, 2]

replace

替換數組元素

a = ["a","b"] 

 

a.replace(["x","y","z"])  

 

p a                 =>["x", "y", "z"] 

reverse

 

 

reverse

將所有元素以逆序重新排列生成新數組並返回它

["a","b","c" ].reverse=> ["c", "b", "a"]

rindex

返回最后一個值相等的元素的索引值

a = [ "a","b","b","b","c"] 

 

a.rindex("b")           => 3 

shift

刪除數組的首元素並返回它。剩余元素依次提前。若數組為空返回nil

args = ["-m","-q","filename"] 

 

args.shift => "-m" 

 

args => ["-q", "filename"] 

sort

 

 

sort!

從小到大排序

a = [ "d", "a", "e", "c", "b" ] 

 

a.sort  => ["a", "b", "c", "d", "e"] 

uniq

 

 

uniq

刪除數組中的重復元素后生成新數組並返回它

a = [ "a", "a", "b", "b", "c" ] 

 

a.uniq    => ["a", "b", "c"] 

unshift

在數組第一個元素前添加元素

a = [ "b", "c", "d" ] 

 

a.unshift("a")  => ["a", "b", "c", "d"] 

to_s

將數組的所有元素連接成字符串

["a","e","i","o"].to_s  => "aeio" 

 


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