exists (sql 返回結果集,為真) not exists (sql 不返回結果集,為真) 如下: 表A ID NAME 1 A1 2 A2 3 A3 表B ID AID NAME 1 1 B1 2 2 B2 3 2 B3 表A和表B是1對多的關系 A.ID => B.AID SELECT ID,NAME FROM A WHERE EXIST (SELECT * FROM B WHERE A.ID=B.AID) 執行結果為 1 A1 2 A2 原因可以按照如下分析 SELECT ID,NAME FROM A WHERE EXISTS (SELECT * FROM B WHERE B.AID=1) ---> SELECT * FROM B WHERE B.AID=1有值,返回真,所以有數據 SELECT ID,NAME FROM A WHERE EXISTS (SELECT * FROM B WHERE B.AID=2) ---> SELECT * FROM B WHERE B.AID=2有值,返回真,所以有數據 SELECT ID,NAME FROM A WHERE EXISTS (SELECT * FROM B WHERE B.AID=3) ---> SELECT * FROM B WHERE B.AID=3無值,返回假,所以沒有數據 NOT EXISTS 就是反過來 SELECT ID,NAME FROM A WHERE NOT EXIST (SELECT * FROM B WHERE A.ID=B.AID) 執行結果為 3 A3 =========================================================================== EXISTS = IN,意思相同不過語法上有點點區別,好像使用IN效率要差點,應該是不會執行索引的原因 SELECT ID,NAME FROM A WHERE ID IN (SELECT AID FROM B) NOT EXISTS = NOT IN ,意思相同不過語法上有點點區別 SELECT ID,NAME FROM A WHERE ID NOT IN (SELECT AID FROM B)