花费 537 ms
js获取 url?后面的参数取值

function GetRequest() { var url = location.search; //获取url中"?"符后的字串 var theRequest = new ...

Wed Jan 02 23:06:00 CST 2019 0 1238

 
粤ICP备18138465号  © 2018-2025 CODEPRJ.COM