思路：原问题可以转换为将数组分割为两个集合 根据符号为正和符号为负划分 ，使得这两个集合和的差最小。 可以等价为 背包问题。那么dp i j 就是将前i个物品放到容量为j的背包能得到的最大值。这里背包容量为total sum ...
2019-05-20 00:52 0 529 推荐指数：
You are given an array of integers stones where stones[i] is the weight of the ith stone. We are playing a game with the stones. On each turn, we ...
We have a collection of stones, each stone has a positive integer weight. Each turn, we choose the two heaviest stones and smash them together. ...
1049. Last Stone Weight II https://leetcode.com/problems/last-stone-weight-ii/ 题意：从一堆石头里任选两个石头s1,s2，若s1==s2,则两个石头都被销毁，否则加入s1<s2，剩下一块重量为s2-s1 ...
最小化差题目 折半枚举 + 二分查找 1755. 最接近目标值的子序列和 2035. 将数组分成两个数组并最小化数组和的差 总和体积小的话，可以转为01包问题 DP 1049. 最后一块石头的重量 II 1755. 最接近目标值的子序列和 题意 给你 ...
原题链接在这里：https://leetcode.com/problems/last-stone-weight/ 题目： We have a collection of rocks, each rock has a positive integer weight. Each turn, we ...
/strengthen/LeetCode➤原文地址：https://www.cnblogs.com/streng ...
There is a stone game.At the beginning of the game the player picks n piles of stones in a circle. The goal is to merge the stones in one ...
Alice and Bob continue their games with piles of stones. There are a number of piles arranged in ...
