[LeetCode] 850. Rectangle Area II 矩形面积之二
We are given a list of (axis-aligned) `rectangles`. Each `rectangle[i] = [x1, y1, x2, y2] `, where (x1, y1) are the coordinates of the bottom-left ...
原文：leetcode 850. Rectangle Area II
给定一些矩形 求覆盖面积 矩形不超过 个 算法 朴素思想 虽然朴素但是代码却有意思 利用容斥原理 复杂度高达 N N 点位压缩，压缩后进行暴力循环 同时压缩x和y 最后返回 N 算法 扫描线算法 将每一个矩形看作一个 事件 这样的事件 注意到刚才的 算法中使用了 区间维护的算法 这里使用线段树维护这个区间 使得达到 NlogN 下面是py 实现线段树 注意这里的 下标实际意义不是 容器 而是 标志 ...
2018-07-17 15:39 0 912 推荐指数：
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