题目 题目链接 Given a non-empty string check if it can be constructed by taking a substring of it and appending multiple copies of the substring together. ...
复习一下KMP算法 KMP的主要思想是利用字符串自身的前缀后缀的对称性,来构建next数组,从而实现用接近O N 的时间复杂度完成字符串的匹配 对于一个字符串str,next j k 表示满足str ...k str j k...j 的最大的k,即对于子串str ...j ,前k个字母等于后k个字母 现在求解str的next数组: 初始化:next 那么在知道了next j 的情况下,如何递推地求 ...
2016-12-03 19:32 0 1538 推荐指数:
题目 题目链接 Given a non-empty string check if it can be constructed by taking a substring of it and appending multiple copies of the substring together. ...
Given a non-empty string check if it can be constructed by taking a substring of it and appending multiple copies ...
Given a string text, we are allowed to swap two of the characters in the string. Find the length of the longest substring with repeated characters. ...
题目链接 Given a string S and a string T, find the minimum window in S which will contain all the chara ...
useful to identify repeated sequences within the DNA. W ...
Given a string S and a string T, find the minimum window in S which will contain all the characters ...
Problem Description: Given a pattern and a string str, find if str follows the same pattern. Here follow means a full match ...
两种解法,动态规划和KMP变种 动态规划,类似于lcs的解法,数组flag[i][j]记录s从i到j是不是回文 首先初始化,i>=j时,flag[i][j]=true,这是因为s[i][i]是单字符的回文,当i>j时,为true,是因为有可能出现flag[2][1]这种情况 ...