昨天在leetcode做题的时候做到了371,原题是这样的: 因为之前完全没有在实际练习中使用过位运算,所以刚看到这道题目的时候我的第一反应是 1.用乘除代替加减,但是一想,觉得恐怕不行,因为乘除本质上也是加减法,不可能跳过加减法做运算。 2.然后又想到或许可以转成二进制再用 ...
Calculate the sum of two integersaandb, but you arenot allowedto use the operator and . Example : Example : Credits:Special thanks to fujiaozhu for adding this problem and creating all test cases. 这道 ...
2016-07-01 08:43 10 18996 推荐指数:
昨天在leetcode做题的时候做到了371,原题是这样的: 因为之前完全没有在实际练习中使用过位运算,所以刚看到这道题目的时候我的第一反应是 1.用乘除代替加减,但是一想,觉得恐怕不行,因为乘除本质上也是加减法,不可能跳过加减法做运算。 2.然后又想到或许可以转成二进制再用 ...
Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would ...
题目描述 给定一个整数数组和一个目标值,找出数组中和为目标值的两个数。 你可以假设每个输入只对应一种答案,且同样的元素不能被重复利用。 示例: 给定 nums = [2, 7, 11, 15], target = 9 因为 nums[0] + nums ...
题目是:Calculate the sum of two integers a and b, but you are not allowed to use the operator + and -. 思路:两个数的加法分为两步,对应位相加和进位。 举个简单的例子:997+24 ...
/strengthen/LeetCode➤原文地址:https://www.cnblogs.com/streng ...
题目要求 Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input ...
Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number.The ...
Given a Binary Search Tree and a target number, return true if there exist two elements in the BST such that their sum is equal to the given ...