315. Count of Smaller Numbers After Self
of smaller elements to the right of nums[i]. Exampl ...
原文：[leetcode] Count of Smaller Numbers After Self
题目： 分析：很显然不能用时间复杂度为O N 的暴力穷举法，下面先给出一个运行时间为 ms的AC答案： 上面的答案虽然AC了，但若原始海量数据本身是降序排列时，再运行时间也为O N ，下面给出运用树状数组 Binary Indexed Tree Fenwick tree 的解法，使时间复杂度将为O NlgN ，树状数组的相关知识可参考博客树状数组. 最后给出线段树 segment tree 的解法 ...
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