从前序中序遍历来重构二叉树 经典题,从期末考试到考研什么的应该都有 前序遍历第一个肯定是root 在inorder里面去找root 左边的是leftsubtree , 右边的是rightsubtree 然后preorder除去order,后面lifetsubtree.size 个是左边的, rightsubtree.size个是右边的 递归构造tree就好了 ...
2014-01-14 17:20 0 2505 推荐指数：
题目： Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 题解 ...
Given preorder and inorder traversal of a tree, construct the binary tree. You may assume that duplicates do not exist ...
原题地址：http://oj.leetcode.com/problems/construct-binary-tree-from-inorder-and-postorder-traversal/ 题意：根据二叉树的中序遍历和后序遍历恢复二叉树。 解题思路：看到树首先想到要用递归来解题。以这道题为 ...
Given inorder and postorder traversal of a tree, construct the binary tree. Note:You may assume that duplicates do not exist in the tree. 递归构造 ...
Given preorder and inorder traversal of a tree, construct the binary tree. Note:You may assume that duplicates do not exist in the tree ...
原题链接在这里：https://leetcode.com/problems/construct-binary-search-tree-from-preorder-traversal/ 题目： Return the root node of a binary search tree ...
Given inorder and postorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree ...
Given a binary tree, return the inorder traversal of its nodes' values. For example:Given binary tree {1,#,2,3}, 非递归版本： 用一个栈来模拟递归的情况， 首先思考inorder ...
