Given a string S and a string T, count the number of distinct subsequences of S which equals T. A subsequence of a string is a new string which ...
问题 给出字符串S和T,计算S中为T的不同的子序列的个数。 一个字符串的子序列是一个由该原始字符串通过删除一些字母 也可以不删 但是不改变剩下字母的相对顺序产生的一个新字符串。如,ACE是ABCDE的一个子序列,但是AEC不是。 这里有一个例子: S rabbbit ,T rabbit 返回值应为 初始思路 要找出子序列的个数,首先要有找出S中为T的子序列的方法。T是S的子序列,首先其每一个字母肯 ...
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Given a string S and a string T, count the number of distinct subsequences of S which equals T. A subsequence of a string is a new string which ...
Given a string S, count the number of distinct, non-empty subsequences of S . Since the result may be large, return the answer modulo 10^9 + 7. ...
引言 子序列和子字符串或者连续子集的不同之处在于,子序列不需要是原序列上连续的值。 对于子序列的题目,大多数需要用到DP的思想,因此,状态转移是关键。 这里摘录两个常见子序列问题及其解法。 例题1, 最长公共子序列 我们知道最长公共子串的求法,先温习一下,它的求法也是使用DP思想 ...
题目: Given a string S and a string T, count the number of distinct subsequences of T in S. A subsequence of a string is a new string which ...
我的LeetCode解题报告索引 题目链接 Given a string S and a string T, count the number of distinct subsequences of T in S. A subsequence of a string is a new ...
Distinct Subsequences Given a string S and a string T, count the number of distinct subsequences of T in S. A subsequence of a string is a new ...
Given string S and a dictionary of words words, find the number of words[i] that is a subsequence ...
Distinct Subsequences Given a string S and a string T, count the number of distinct subsequences of T in S. A subsequence of a string is a new ...