我的LeetCode解题报告索引 题目链接 Given a string S and a string T, count the number of distinct subsequences of T in S. A subsequence of a string is a new ...
题意: 给定 个字符串a, b,求b在a中出现的次数。要求可以是不连续的,但是b在a中的顺序必须和b以前的一致。 思路: 类似于数字分解的题目。dp i j 表示:b的前j个字符在a的前i个字符中出现的次数。 似乎这种表示方法司空见惯,但是一开始我还真没能搞懂如何去递推。事情的真相是: 如果a i b j 则 dp i j dp i j dp i j 如果a i b j 则 dp i j dp i ...
2012-11-16 11:26 0 4384 推荐指数:
我的LeetCode解题报告索引 题目链接 Given a string S and a string T, count the number of distinct subsequences of T in S. A subsequence of a string is a new ...
题目: Given a string S and a string T, count the number of distinct subsequences of T in S. A subsequence of a string is a new string which ...
Distinct Subsequences Given a string S and a string T, count the number of distinct subsequences of T in S. A subsequence of a string is a new ...
Distinct Subsequences Given a string S and a string T, count the number of distinct subsequences of T in S. A subsequence of a string is a new ...
问题 给出字符串S和T,计算S中为T的不同的子序列的个数。 一个字符串的子序列是一个由该原始字符串通过删除一些字母(也可以不删)但是不改变剩下字母的相对顺序产生的一个新字符串。如,ACE是ABCD ...
Given a string S and a string T, count the number of distinct subsequences of S which equals T. A subsequence of a string is a new string which ...
Given a string S, count the number of distinct, non-empty subsequences of S . Since the result may be large, return the answer modulo 10^9 + 7. ...
Max Sum Time Limit:1000MS Memory Limit:32768KB 64bit IO Format:%I64d & %I64u Subm ...