"""check whether some letters lies in one word"""
word = "paramount"
letters = 'para'
if letters in word.lower():
print("True")
print(letters)
print("#check if two words share common letters, if so, print them out.")
inter = set(word).intersection(set(letters))
print(inter)
print("#Member Operator in")
str = "Sstring test using member operator in string test using member operator in"
member1 = "str"
member2 = "usi"
print(member1 in str, member2 in str)
print("mem" not in str)
print("#work wtih the methods of string object: find(), rfind(), index(), rindex()")
"""
find()和index()的区别:
方法 区别
find() 获取值时，如果要查找的值不存在，会返回-1
index() 获取值的索引时，如果不存在值，会报错
"""
print(str.find(member1))
print(str.find(member2))
print(str.rfind(member1))
print(str.rfind(member2))
print(f"index(): {str.index(member1)}")
print(f"index(): {str.index(member2)}")
print(f"rindex(): {str.index(member1)}")
print(f"rindex(): {str.index(member2)}")
str = "I like China"
print(f"count(): {str.count(member1)}")
print(f"count(): {str.count(member2)}")
python判断字符串包含关系
转自---http://blog.csdn.net/yl2isoft/article/details/52079960
1.使用成员操作符 in
>>> s='nihao,shijie'
>>> t='nihao'
>>> result = t in s
>>> print result
True2.使用string模块的find()/rfind()方法
>>> import string
>>> s='nihao,shijie'
>>> t='nihao'
>>> result = string.find(s,t)!=-1
>>> print result
True
>>> result = string.rfind(s,t)!=-1
>>> print result
True 3.使用string模块的index()/rindex()方法
index()/rindex()方法跟find()/rfind()方法一样，只不过找不到子字符串的时候会报一个ValueError异常。
import string
def find_string(s,t):
try:
string.index(s,t)
return True
except(ValueError):
return False
s='nihao,shijie'
t='nihao'
result = find_string(s,t)
print result #True
4.使用字符串对象的find()/rfind()、index()/rindex()和count()方法
>>> s='nihao,shijie'
>>> t='nihao'
>>> result = s.find(t)>=0
>>> print result
True
>>> result=s.count(t)>0
>>> print result
True
>>> result=s.index(t)>=0
>>> print result
True
参考链接：https://www.cnblogs.com/johnson-yuan/p/7910087.html