Newtonsoft.Json解析数组

以下是遗传json数组：

var jsonInfo=[{"name":"abc","id":"1","count":0},{"name":"def","id":"2","count":1}]

如果使用传统的JsonConvert.DeserializeObject方法会报错，这时需要使用以下方法：

var arrdata = Newtonsoft.Json.Linq.JArray.Parse(jsoninfo);

List<UserInfo> obj2 = arrdata.ToObject<List<UserInfo>>();

 

string json = @"{
  CPU: 'Intel',
  Drives: [
    'DVD read/writer',
    '500 gigabyte hard drive'
  ]
}";

JObject o = JObject.Parse(json);

　　

string json = @"[
  'Small',
  'Medium',
  'Large'
]";

JArray a = JArray.Parse(json);

　　

using (StreamReader reader = File.OpenText(@"c:\person.json"))
{
    JObject o = (JObject)JToken.ReadFrom(new JsonTextReader(reader));
    // do stuff
}