python实现文件名得模糊匹配

def find(dir, name):
    # print(dir)
    for i in [x for x in os.listdir(dir) if os.path.isfile(os.path.join(dir, x)) and name in os.path.splitext(x)[0]]:
        print(os.path.join(dir, i))
    # os.path.isfile() 需要完整路径或者相对当前目录的相对路径
    for i in [x for x in os.listdir(dir) if os.path.isdir(os.path.join(dir, x))]:
        if os.listdir(os.path.join(dir, i)):
            # 防止因为权限问题报错
            try:
                find(os.path.join(dir, i), name)
            except:
                pass


find('E:\\收藏夹\\C41\\C41', 'dod')