pyhton中实现列表元素顺序颠倒


 

1、循环

>>> test1 = ["aa","bb","cc","dd","ee","ff","gg"] >>> test1 ['aa', 'bb', 'cc', 'dd', 'ee', 'ff', 'gg'] >>> test2 = [] >>> test2 [] >>> for i in range(-1,-(len(test1)+1),-1): test2.append(test1[i]) >>> test2 ['gg', 'ff', 'ee', 'dd', 'cc', 'bb', 'aa']

 

2、列表分片

>>> test1[::1]
['aa', 'bb', 'cc', 'dd', 'ee', 'ff', 'gg', 'hh', 'ii', 'jj']
>>> test1[::-1]
['jj', 'ii', 'hh', 'gg', 'ff', 'ee', 'dd', 'cc', 'bb', 'aa']

 

3、就地反转

>>> test1 = ["aaa","bbb","ccc","ddd"] >>> test1 ['aaa', 'bbb', 'ccc', 'ddd'] >>> test2 = test1[:] >>> test2 ['aaa', 'bbb', 'ccc', 'ddd'] >>> test1.reverse() >>> test1 ['ddd', 'ccc', 'bbb', 'aaa'] >>> test2[::-1] ['ddd', 'ccc', 'bbb', 'aaa'] >>> test2 ['aaa', 'bbb', 'ccc', 'ddd']

 


免责声明!

本站转载的文章为个人学习借鉴使用,本站对版权不负任何法律责任。如果侵犯了您的隐私权益,请联系本站邮箱yoyou2525@163.com删除。



 
粤ICP备18138465号  © 2018-2025 CODEPRJ.COM