Python 遍历一个目录，输出所有的文件名

python 获取一个文件夹内(包括子文件夹)所有文件的名字和路径

import os dir = "e:\\" for root, dirs, files in os.walk(dir): for file in files: print os.path.join(root,file)

或：

import os path = r'e:\case' fns = [os.path.join(root,fn) for root, dirs, files in os.walk(path) for fn in files] for f in fns: print(f) print(len(fns))

#coding=utf-8 import os def GetFileList(dir, fileList): newDir = dir if os.path.isfile(dir): fileList.append(dir.decode('gbk')) elif os.path.isdir(dir): for s in os.listdir(dir): #如果需要忽略某些文件夹，使用以下代码 #if s == "xxx": #continue newDir=os.path.join(dir,s) GetFileList(newDir, fileList) return fileList list = GetFileList('D:\\workspace\\PyDemo\\fas', []) for e in list: print e