效果如图
--该函数把传递过来的字符串转换成IN 后面的列表，可以处理以分号，逗号以及空格分隔的字符串
CREATE FUNCTION [dbo].[GetInStr]
(@SourceStr varchar(8000))--源字符串
RETURNS @table table(list varchar(100) )
AS
BEGIN
select @sourcestr = replace(@sourcestr,';',',')
select @sourcestr = replace(@sourcestr,'\',',')
--select @sourcestr = replace(@sourcestr,'.',',')
-- select @sourcestr = replace(@sourcestr,' ',',')
--declare @OutStr varchar(200)
if charindex(',',@sourcestr)>0
begin
declare @i int
declare @n int
set @i=1
while charindex(',',@sourcestr,@i)>0
begin
set @n=charindex(',',@sourcestr,@i)
insert into @table values(substring(@sourcestr,@i, @n-@i) )
set @i=@n+1
end
insert into @table values(substring(@sourcestr,@i,len(@sourcestr)-@i+1))
end else insert into @table values(@sourcestr)
delete from @table where isnull(list,'') = ''
return
END