将结构体通过memcpy转换为数组

#include <stdio.h>
#include <stdlib.h>
/******************
测试将结构体通过memcpy转换为数组的可行性
******************/
typedef struct TEST
{
    short a;
    short b;
    short c;
};
struct TEST1
{
    char a;
    short b;
    int c;
    char* d;
};

int main()
{
    struct TEST test;
    struct TEST1 test1;
    char tmp[10];
    short buf[10];
    char i;

    test.a = 0x1A10;
    test.b = 0x2B11;
    test.c = 0x3C12;

    memcpy(buf, &test, sizeof(test));

    printf("sizeof(char) = %d\r\n", sizeof(char));
    printf("sizeof(short) = %d\r\n", sizeof(short));
    printf("sizeof(int) = %d\r\n", sizeof(int));
    printf("sizeof(char*) = %d\r\n", sizeof(char*));
    printf("sizeof(short*) = %d\r\n", sizeof(short*));
    printf("sizeof(int*) = %d\r\n", sizeof(int*));

    printf("\r\nsizeof(test) = %d\r\n", sizeof(test));

    for(i=0;i<sizeof(test);i++)
    {
        printf("buf[%d] = %x\r\n", i, buf[i]);
    }

    printf("------------------\r\n");

    memcpy(tmp, &test, sizeof(test));

    for(i=0;i<sizeof(test);i++)
    {
        printf("tmp[%d] = %x\r\n", i, tmp[i]);
    }

    printf("------------------\r\n");

    printf("sizeof(test1) = %d\r\n", sizeof(test1));

    test1.a = 0x11;
    test1.b = 0x1203;
    test1.c = 0x13243567;
    test1.d = "ABC";

    //printf("test1.a = %x\r\n", test1.a);
    //printf("test1.b = %x\r\n", test1.b);
    //printf("test1.c = %x\r\n", test1.c);
    //printf("test1.d = %s\r\n", test1.d);

    memcpy(buf, &test1, sizeof(test1));

    for(i=0;i<sizeof(test1);i++)
    {
        printf("buf[%d] = %x\r\n", i, buf[i]);
    }

    printf("------------------\r\n");

    memcpy(tmp, &test1, sizeof(test1));

    for(i=0;i<sizeof(test1);i++)
    {
        printf("tmp[%d] = %x\r\n", i, tmp[i]);
    }
    return 0;
}

结论：可行