DataFrame(9)：DataFrame运算——累计统计函数

1、相关函数说明

2、原始数据

df = pd.DataFrame({"id":["00{}".format(i) for i in range(1,10)],
                   "score":[2,3,4,4,5,6,7,7,8]})
display(df)

结果如下：

            

3、cumsum()函数：求前n个元素的累积值

(很重要的一个函数)

df = pd.DataFrame({"id":["00{}".format(i) for i in range(1,10)],
                   "score":[2,3,4,4,5,6,7,7,8]})
display(df)

df["cumsum"] = df["score"].cumsum(axis=0)
display(df)

结果如下：

            

1）cumsum()：分组求累计值

df = pd.DataFrame({"id":["001","001","002","003","001","002","002","003","003"],
                   "score":[2,3,4,4,5,6,7,7,8]})
display(df)

df["分组求累计值"] = df.groupby("id").cumsum()
df = df.sort_values(by=["id"])
display(df)

结果如下：

            

4、cummax()函数：求前n个元素中的最大值

df = pd.DataFrame({"score":[1,2,1,5,2,6,3,7,1]})
display(df)

df["前n个值中最大值"] = df["score"].cummax(axis=0)
display(df)

结果如下：

            

1）cummax()函数：分组求前n个元素中的最大值

df = pd.DataFrame({"id":["001","001","002","003","001","002","002","003","003"],
                   "date":["2020-01-01","2020-01-09","2020-01-05","2020-01-03",
                           "2020-01-08","2020-01-07","2020-01-02","2020-01-04","2020-01-06"],
                   "score":[1,2,1,5,2,6,3,7,1]})
display(df)

df = df.sort_values(by=["id","date"],ascending=[True,True])
df["前n个值中最大值"] = df.groupby("id")["score"].cummax()
display(df)

结果如下：

            

注意：cummin()函数的用法和cummax()函数的用法一致，可以自行下去尝试。  

5、cumprod()函数：求前n个元素的累乘积

df = pd.DataFrame({"score":[1,2,1,5,2,6,3,7,1]})
display(df)

df["前n个值的累乘积"] = df["score"].cummax(axis=0)
display(df)

结果如下：

            

注意：对于分组求前n个元素的累乘积，和上面用法一致。