python3 处理列表嵌套字典去重

def list_dict(dictlist):
        def function(date):
            return date['ip']

        dictlist_new = []
        for list_dict in dictlist:
            list_dict['backPath'] = [list_dict['backPath']]
            dictlist_new.append(list_dict)
        resource_new = []
        num = 0
        dictlist_new.sort(key=function)
        for dictlist in dictlist_new:
            if num == 0:
                resource_new.append(dictlist)
            else:
                if resource_new[0]['ip'] != dictlist['ip']:
                    old = resource_new[0]
                    del resource_new[0]
                    resource_new.append(dictlist)
                    resource_new.append(old)
                elif resource_new[0]['ip'] == dictlist['ip']:
                    resource_new[0]['backPath'].append(dictlist['backPath'][0])
            num += 1
        return resource_new


resource_list = [
        {"ip": "10.23.13.8", "backPath": '/usr/sap/1111', "user": "root", "PASSWD": "1212121"},
        {"ip": "10.23.13.8", "backPath": "/usr/sap/1112", "user": "root", "PASSWD": "1212121"},
        {"ip": "10.23.13.9", "backPath": "/usr/sap/1111", "user": "root", "PASSWD": "1212121"},
        {"ip": "10.23.13.10", "backPath": "/usr/sap/1111", "user": "root", "PASSWD": "1212121"},
        {"ip": "10.23.13.8", "backPath": "/usr/sap/1113", "user": "root", "PASSWD": "1212121"}
]

print(list_dict(resource_list))


"""
整体思路就是将需要合并的字段改为列表
再通过主键的方式校验重复，如果主键重复就将需要合并的字段添加到新的列表中。
不重复则直接返回并将自己添加到一个新列表中
"""