element el-tree循环遍历树形结构,并动态赋值disabled属性


<style scoped>
.form {
  width: 50%;
}
</style>

<template>

<div class="form">

<el-tree
  :data="data2"
  show-checkbox
  node-key="id"
  default-expand-all
  :props="defaultProps">
</el-tree>
</div>

</template>

<script>
export default {
  data() {
    return {
      data2: [
        {
          fs: 0,
          id: 1,
          label: "一级 1",
          children: [
            {
              fs: 0,
              id: 4,
              //   disabled:true,
              label: "二级 1-1",
              children: [
                {
                  fs: 1,
                  id: 9,
                  label: "三级 1-1-1"
                },
                {
                  fs: 1,
                  id: 10,
                  label: "三级 1-1-2"
                }
              ]
            }
          ]
        },
        {
          fs: 0,
          id: 2,
          label: "一级 2",
          children: [
            {
              fs: 0,
              id: 5,
              label: "二级 2-1"
            },
            {
              fs: 1,
              id: 6,
              label: "二级 2-2"
            }
          ]
        },
        {
          fs: 0,
          id: 3,
          label: "一级 3",
          children: [
            {
              fs: 0,
              id: 7,
              label: "二级 3-1"
            },
            {
              fs: 0,
              id: 8,
              label: "二级 3-2"
            }
          ]
        }
      ],
      defaultProps: {
        children: "children",
        label: "label"
      }
    };
  },
  methods: {
    tickMenuIdFilter: function() {
      var resultArr = new Array();
      var getTickMenuId = function(obj) {
        if (undefined == obj || null == obj || !obj instanceof Object) {
          return;
        }
        if (obj.fs > 0) {
          // console.log('obj',obj)
          obj.disabled = true;
          resultArr.push(obj.id);
        }
        if (null != obj.children && obj.children instanceof Array) {
          for (let child of obj.children) {
            getTickMenuId(child);
          }
        }
      };

      return {
        filter: function(arr) {
          if (!arr instanceof Array) {
            return false;
          }
          resultArr = new Array();
          for (let rootMenu of arr) {
            getTickMenuId(rootMenu);
          }
          return resultArr;
        }
      };
    }
  },
  created() {
    this.tickMenuIdFilter().filter(this.data2);
    console.log("data2", this.data2[0].children[0]);
  }
};
</script>


免责声明!

本站转载的文章为个人学习借鉴使用,本站对版权不负任何法律责任。如果侵犯了您的隐私权益,请联系本站邮箱yoyou2525@163.com删除。



 
粤ICP备18138465号  © 2018-2025 CODEPRJ.COM