React中子组件无法进行路由跳转的问题

1、子组件引入withRouter
2、跳转路由this.props.history.push(’/’);
3、加入： export default withRouter(Title);

import {withRouter} from "react-router-dom"; class Title extends Component { outLogin = () => { //跳转路由 
  this.props.history.push('/'); } }
 export default withRouter(Title); 

 

原文链接：https://blog.csdn.net/Hei_lovely_cat/java/article/details/104038229