python如何实现查找特定名称文件

遍历”Day1-homework”目录下文件；
找到文件名包含“2020”的文件；
将文件名保存到数组result中；
按照序号、文件名分行打印输出。

 

#导入OS模块
import os
#待搜索的目录路径
path = "Day1-homework"
#待搜索的名称
filename = "2020"
#定义保存结果的数组
result = []

def findfiles(files_path, files_list):
    #查找文件代码
    files = os.listdir(files_path)
    for s in files:
        s_path = os.path.join(files_path, s)
        if os.path.isdir(s_path):
            findfiles(s_path, files_list)
        elif os.path.isfile(s_path) and '2020' in s:
            result.append(s_path)


if __name__ == '__main__':
    findfiles(path,result)
    for i in range(len(result)):
        print("[{} ,".format(i)+"'"+result[i]+"\']")

[0 ,'Day1-homework/18/182020.doc']
[1 ,'Day1-homework/26/26/new2020.txt']
[2 ,'Day1-homework/4/22/04:22:2020.txt']