python创建多维字典方法


python不直接创建多维字典,需要逐层判断不存在创建,存在追加:

例如:

不能直接

dictName['key1']['key2']['key3']['key4']['key5'] = ['123', '456']

 

下面函数实现:

def createDict(tupleVals, val):
tupNum = len(tupleVals)
tempName = dictName = {}
for index, tupleVal in enumerate(tupleVals):
if index == tupNum - 1:
dictName[tupleVal] = val
else:
if tupleVal not in dictName.keys():
dictName[tupleVal] = {}
else:
dictName.update({tupleVal: {}})
dictName = dictName[tupleVal]
return tempName

dictName = createDict(('key1', 'key2', 'key3', 'key4', 'key5'), ['123', '456'])
print(dictName['key1']['key2']['key3'])


免责声明!

本站转载的文章为个人学习借鉴使用,本站对版权不负任何法律责任。如果侵犯了您的隐私权益,请联系本站邮箱yoyou2525@163.com删除。



 
粤ICP备18138465号  © 2018-2025 CODEPRJ.COM