对List里的map的某个属性重复的值进行处理的方法

package test;

import java.util.*;
import java.util.stream.Collectors;

public class Test5 {

    public static void main(String[] args) {

        List<LinkedHashMap<String, Object>> list = new ArrayList<>();
        list.add(new LinkedHashMap<String, Object>() {{
            put("id", "a");
            put("age", "13");
            put("sex", "男");
        }});
        list.add(new LinkedHashMap<String, Object>() {{
            put("id", "a");
            put("age", "14");
            put("sex", "男");
        }});
        list.add(new LinkedHashMap<String, Object>() {{
            put("id", "b");
            put("age", "14");
            put("sex", "男");
        }});
        list.add(new LinkedHashMap<String, Object>() {{
            put("id", "c");
            put("age", "14");
            put("sex", "男");
        }});
        list.add(new LinkedHashMap<String, Object>() {{
            put("id", "");
            put("age", "14");
            put("sex", "男");
        }});
        list.add(new LinkedHashMap<String, Object>() {{
            put("id", "c");
            put("age", "14");
            put("sex", "男");
        }});


        handleRepeatPrimaryKey(list, "id");
        List<LinkedHashMap<String, Object>> hasList = new ArrayList<>();
        hasList = list.stream().filter(x -> !x.get("id").toString().equals("")).collect(Collectors.toList());
        List<LinkedHashMap<String, Object>> notHasList = new ArrayList<>();
        notHasList = list.stream().filter(x -> x.get("id").toString().equals("")).collect(Collectors.toList());

        System.out.println(hasList);
        System.out.println(notHasList);


    }


    public static List<LinkedHashMap<String, Object>> handleRepeatPrimaryKey(List<LinkedHashMap<String, Object>> list, String id) {
        List<LinkedHashMap<String, Object>> itemList = new ArrayList<>();
        for (LinkedHashMap<String, Object> lhm : list) {
            if (itemList.size() == 0) {
                itemList.add(lhm);
            } else {
                ListIterator<LinkedHashMap<String, Object>> listIterator = itemList.listIterator();
                while (listIterator.hasNext()) {
                    if (listIterator.next().get(id).toString().equals(lhm.get(id).toString())) {
                        lhm.put(id, "");
                    }
                }
// 注意放在循环外面
                listIterator.add(lhm);
            }
        }
        return list;
    }
}

对重复主键进行处理，取第一个，剩余的主键都置空，嗯，能满足我的需求。不知道还有没有更好的方法？