Python使用groupby之字典分组

需求：根据列表中字段元素某个(些)字段分组

解决方案: functiontools中groupby函数进行分组，使用这个函数前必须先要排序，可通过使用operator 模块的itemgetter 函数，可以非常容易的排序这样的数据结构。

data=[

　　{'id': '078af4a6228047dba0' , 'main_code': 'TJ' , 'code': 'XC001' , ‘groupid’: 0 , 'column_name': 'name' , 'column_value': '张三'},

　　{'id': '078af4a6228047dba0' , 'main_code': 'TJ', 'code': 'XC001' , ‘groupid’: 0, 'column_name': 'age' , 'column_value': '27'},

　　{'id':'078af4a6228047dba0', 'main_code': 'TJ','code':'XC001',‘groupid’:1,'column_name':'name','column_value':'李四'},

　　{'id':'078af4a6228047dba0', 'main_code': 'TJ','code':'XC001',‘groupid’:1,'column_name':'age','column_value':'45'},

　　{'id': '078af4a6228047dba0' , 'main_code': 'LP' , 'code': 'XC001' , ‘groupid’: 0 , 'column_name': 'name' , 'column_value': '张三'},

　　{'id': '078af4a6228047dba0' , 'main_code': 'LP', 'code': 'XC001' , ‘groupid’: 0, 'column_name': 'age' , 'column_value': '27'},

　　{'id':'078af4a6228047dba0', 'main_code': 'LP','code':'XC001',‘groupid’:1,'column_name':'name','column_value':'李四'},

　　{'id':'078af4a6228047dba0', 'main_code': 'LP','code':'XC001',‘groupid’:1,'column_name':'age','column_value':'45'},

　　{'id':'078af4a6228047dba0', 'main_code': 'TJ','code':'RY002',‘groupid’:0,'column_name':'sex','column_value':'男'},

　　{'id':'82970de3e3b836d34', 'main_code': 'TJ','code':'BD001',‘groupid’:0,'column_name':'isEnable','column_value':True}

]

from operator import itemgetter
from itertools import groupby
import json
data.sort(key=itemgetter('id'))
datas = []
# id分组
for id, items in groupby(data, key=itemgetter('id')):
    data_dict = {'id': id}
    for code_info, item in groupby(items, key=itemgetter('main_code','code')):
        if code_info[0]:
            column=[]
            list_item=[i for i in item]
            list_item.sort(key=itemgetter('groupid'))
            for group_id,g_item in groupby(list_item,key=itemgetter('groupid')):
                column_dict = {}
                for gi in g_item:
                    column_dict[gi.get('column_name')] = gi.get('column_value')
                column_dict['group_id'] = group_id
                column.append(column_dict)
                data_dict[f'{code_info[0]}{code_info[1]}'] = column if len(column)>1 else column[0]
        else:
            data_dict[f'{code_info[0]}{code_info[1]}'] = '无数据'
    datas.append(data_dict)
print(json.dumps(datas,ensure_ascii=False))

 

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