from sympy import *
import numpy as np
from numpy import linalg
# 方程中的符号
x = Symbol('x')
# 计算
result1 = solve(x**2 - 2*x - 2, x)
print("result1[0] = %s" %float(result1[0]))
result2 = solve((np.e)**((5-x)**2) - 8, x)
print("result2 = %s" %result2)
from sympy import *
import numpy as np
from numpy import linalg
# 方程中的符号
x = Symbol('x')
# 计算
result1 = solve(x**2 - 2*x - 2, x)
print("result1[0] = %s" %float(result1[0]))
result2 = solve((np.e)**((5-x)**2) - 8, x)
print("result2 = %s" %result2)
本站转载的文章为个人学习借鉴使用,本站对版权不负任何法律责任。如果侵犯了您的隐私权益,请联系本站邮箱yoyou2525@163.com删除。