es6方法过滤掉两个数组中对象id值相等的项

let arr1=[{id:1,name:'张三'},{id:2,name:'李四'}] let arr2=[{id:1,name:'张三'},{id:3,name:'王五'},{id:44,name:'王柳'},{id:45,name:'王琦'},] let add=arr2.filter(item=>!arr1.some(ele=>ele.id===item.id)) console.log(add)

const arr1 = [{ id: 1, name: '网' }, { id: 2, name: '二位' }]; const arr2 = [{ id: 1, name: '老二' }, { id: 3, name: '老三' }]; // 获取到arr1的所有id集合 let arr1Ids = arr1.map(item => item.id); // 过滤arr2中不包含arr1相同的id数组。 const result = arr2.filter(item => !arr1Ids.includes(item.id)); console.log(result); // [{id: 3, name: "老三"}];