需要改变迭代对象 for(auto &i:s)
string s = "hello"; for (auto &i : s ) i = toupper(i); //改变成大写,影响s的值
cout<<s<<endl; //s的值是 HELLO
不需要改变迭代对象 for(auto i:s)
string s = "hello"; for (auto i : s ) i = toupper(i); //改变成大写,不影响s的值
cout<<s<<endl; //s的值是 hello
迭代map
#include <iostream> #include <map>
using namespace std; int main() { map<int,string> student; student.insert(pair<int,string>(2,"li")); student.insert(pair<int,string>(1,"wang")); student.insert(pair<int,string>(3,"sun")); for(auto &v : student) // for(auto v : student)也是可以的
cout<<"key: "<<v.first<<" | value: "<<v.second<<endl; return 0; }