mysql 查找在另一张表不存在的数据

有两个表Phone_book, Call：

Phone_book +----+------+--------------+ | id | name | phone_number | +----+------+--------------+ | 1 | John | 111111111111 | +----+------+--------------+ | 2 | Jane | 222222222222 | +----+------+--------------+ Call +----+------+--------------+ | id | date | phone_number | +----+------+--------------+ | 1 | 0945 | 111111111111 | +----+------+--------------+ | 2 | 0950 | 222222222222 | +----+------+--------------+ | 3 | 1045 | 333333333333 | +----+------+--------------+

在Call中找出phone_number不在Phone_book的记录，即结果：

Call +----+------+--------------+ | id | date | phone_number | +----+------+--------------+ | 3 | 1045 | 333333333333 | +----+------+--------------+

有三种方法：

1.
SELECT  *
FROM    Call
WHERE   phone_number NOT IN (SELECT phone_number FROM Phone_book)

2.
SELECT *
FROM   Call
WHERE  NOT EXISTS
  (SELECT *
   FROM   Phone_book
   WHERE  Phone_book.phone_number = Call.phone_number)

3.
SELECT * 
FROM   Call
LEFT OUTER JOIN Phone_Book
  ON (Call.phone_number = Phone_book.phone_number)
  WHERE Phone_book.phone_number IS NULL

 

见https://stackoverflow.com/questions/367863/sql-find-records-from-one-table-which-dont-exist-in-another