页面跳转时候拼接在url后面的多个 参数获取

  function GetRequest() {
        var url = location.search;
        var theRequest = new Object();
        if (url.indexOf("?") != -1) {
            var str = url.substr(1);
            strs = str.split("&");
            for (var i = 0; i < strs.length; i++) {
                theRequest[strs[i].split("=")[0]] = decodeURI(strs[i].split("=")[1]);
            }
        }
        console.log(theRequest)
        return theRequest;
    }
    var params={};
    params=GetRequest();
    var processDefinitionName=params['processDefinitionName'];