截取url地址?后面参数

function GetRequest() {
var url = location.search; //获取url中"?"符后的字串
var theRequest = new Object();
if (url.indexOf("?") != -1) {
var str = url.substr(1);
strs = str.split("&");
for(var i = 0; i < strs.length; i ++) {
theRequest[strs[i].split("=")[0]]=unescape(strs[i].split("=")[1]);
}
}
return theRequest;
}
var Request = new Object();

Request = GetRequest();
console.log(Request);

//打印出的就是json格式的可以直接使用

 

function GetUrl() {
   var jsons = {},
      jsond = {}
   var url = window.location.href;
   //console.log(url)
   if(url.indexOf('?') > 0) {
      var url = url.split("?")[1];

      function countInstances(mainStr, subStr) {
         var count = 0;
         var offset = 0;
         do {
            offset = mainStr.indexOf(subStr, offset);
            if(offset != -1) {
               count++;
               offset += subStr.length;
            }
         } while (offset != -1)
         return count;
      }

      var num = countInstances(url, '&')

      if(num == 0) {
         var a = url.split('&')
         k = '', v = ''
         k = url.substr(0, url.indexOf('='))
         v = url.substr(url.indexOf('=') + 1)
         jsons[k] = v
      } else {
         var a = url.split('&')
         var jsons = {},
            jsond = {},
            k, v
         for(var i = 0; i < a.length; i++) {
            k = '', v = ''
            k = a[i].substr(0, a[i].indexOf('='))
            v = a[i].substr(a[i].indexOf('=') + 1)
            jsons[k] = v
         }
      }
      return jsons
   }
}

这个方法就简单啦

var arr=GetUrl();
注:xxxx为url地址后面的参数名
var xxxx = arr.xxxx;